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Objective The student will be able to:. solve equations using multiplication and division. Designed by Skip Tyler, Edited by Mr. Nealey. 1) Solve. -5t = 60. To get the variable by itself, which number needs to be moved? -5

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objective the student will be able to
ObjectiveThe student will be able to:

solve equations using multiplication and division.

Designed by Skip Tyler, Edited by Mr. Nealey

1 solve 5t 60
1) Solve. -5t = 60

To get the variable by itself, which number needs to be moved?

-5

To move the -5, you have to do the opposite operation. What operation will we use?

division

1 solve 5t 601
1) Solve -5t = 60

-5 -5

t = -12

-5(-12) = 60

  • Draw a line to separate the equation into 2 sides
  • Inverse Operations: Divide both sides by -5
  • Simplify
  • Check your answer
2 solve 15 6n

6 6

2.5 = n

15 = 6(2.5)

  • Draw a line.
  • Inverse Operations: Divide both sides by 6
  • Simplify
  • Check your answer

2) Solve 15 = 6n

3 solve 3v 129

Answer Now

3) Solve -3v = -129
  • v = -126
  • v = -43
  • v = 43
  • v = 126
4 solve
4) Solve

You don’t like fractions? Let’s get rid of them! 

“Clear the fraction”

by multiplying both sides of the equation by the denominator.

4 solve1

Draw a line

  • Clear the fraction – multiply both sides by 4
  • Simplify
  • Check your answer

4) Solve

4 ·· 4

x = -48

5 solve 18
5) Solve = 18

3 · = 18 · 3

2x = 54

2 2

x = 27

  • Draw a line
  • Clear the fraction – multiply both sides by 3
  • Simplify
  • Inverse Operations: Divide both sides by 2
  • Simplify
  • Check your answer
6 which step clears the fraction in

Answer Now

6) Which step clears the fraction in
  • Multiply by 3
  • Multiply by 5
  • Multiply by -12
  • Multiply by -5
7 solve

Answer Now

7) Solve
  • b = -56
  • b = -14
  • b = 14
  • b = 56