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This explanation explores the properties of a one-end open pipe measuring 3.6 m in length. It calculates the wavelength of the 4th harmonic and determines the wave speed with a frequency of 112 Hz. The fourth harmonic in an open pipe is derived from the formula (7/4)λ = length of the pipe, leading to a wavelength (λ) of approximately 2.057 m. Furthermore, using the wave speed formula (v = fλ), the wave speed is determined to be about 230.4 m/s, demonstrating the relationship between frequency, wavelength, and speed in wave mechanics.
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A one end open pipe is 3.6 m long. What is the wavelength of the 4th harmonic, and what is the wave speed if it has a frequency of 112 Hz? 230.4 ≈ 230 m/s
A one end open pipe is 3.6 m long. What is the wavelength of the 4th harmonic, and what is the wave speed if it has a frequency of 112 Hz? 3.6 m = (7/4)λ, λ = 2.057 m v = f λ = (112 Hz)(2.057 m) = 230.4 ≈ 230 m/s