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Mastering Chemical Equations and Stoichiometry Calculations

Dive into chemical equations, reactant limitations, and solution concentrations. Explore reactions, yields, and dilutions. Learn the law of conservation of matter and perfect your balancing skills. Practice calculations to determine reactant amounts and product yields. Chemistry can be fun!

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Mastering Chemical Equations and Stoichiometry Calculations

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  1. CHAPTER THREECHEMICAL EQUATIONS & REACTION STOICHIOMETRY Goals • Chemical Equations • Calculations Based on Chemical Equations • The Limiting Reactant Concept • Percent Yields from Chemical Reactions • Sequential Reactions • Concentrations of Solutions • Dilution of solutions • Using Solutions in Chemical Reactions

  2. Chemical Equations • Symbolic representation of a chemical reaction that shows: • reactants on left side of reaction • products on right side of equation • relative amounts of each using stoichiometric coefficients

  3. Chemical Equations

  4. Chemical Equations • Look at the information an equation provides: reactants yields products 1formula unit 3 molecules 2 atoms 3 molecules 1 mole 3 moles 2 moles 3 moles 159.7 g 84.0 g 111.7 g 132 g

  5. Chemical Equations • Law of Conservation of Matter • There is no detectable change in quantity of matter in an ordinary chemical reaction. • Balanced chemical equations must always include the same number of each kind of atom on both sides of the equation.

  6. Law of Conservation of Matter • NH3 burns in oxygen to form NO & water

  7. Law of Conservation of Matter • C7H16 burns in oxygen to form carbon dioxide and water. • Balancing equations is askill acquired only with lots of practice

  8. Calculations Based on Chemical Equations • How many CO molecules are required to react with 25 formula units of Fe2O3? 25 Fe2O3 + ? CO  Product 1Fe2O3 needs 3 CO 25Fe2O3 needs ? CO

  9. Calculations Based on Chemical Equations • How many iron atoms can be produced by the reaction of 2.50 x 105 formula units of iron (III) oxide with excess carbon monoxide? Fe2O3 + excess CO  2 Fe + 1Fe2O3 gives 2 Fe 2.5 X 105 Fe2O3 gives ? Fe

  10. Calculations Based on Chemical Equations • What mass of CO is required to react with 146 g of iron (III) oxide? Fe2O3 + 3CO  Product MW(Fe2O3) needs 3MW(CO) 146 g needs ?g CO Chemistry is fun!

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