1 / 19

Revision

Revision. Assume we have a group of 10 rats daily injected with 50 µg Pb /kg b. wt. At the end of experiment, the Pb concentrations in the liver and kidney were measured and tabulated as mean ± standard error in the following table:.

ainsley-puckett
Download Presentation

Revision

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Revision Assume we have a group of 10 rats daily injected with 50 µg Pb/kg b. wt. At the end of experiment, the Pb concentrations in the liver and kidney were measured and tabulated as mean ± standard error in the following table: Is there any significant difference between the liver and kidneys in the levels of accumulated Pb at confidence level 95%?

  2. Solution: So we want to test the null hypothesis H0: σ22 = σ12 against the alternate hypothesis HA: σ22≠ σ12 (2-tailed) d.f.= 10 – 1 = 9 F0.025(9,9) = 4.03 In this case, Fcalc(17.78) > Ftabulated(4.03), so we reject H0that the two standard deviations are unequal,so P < 0.05

  3. Three diets (I, II, III) for mice were tested for differences in body weight (in grams) after a specified period of time. The results are recorded in the following table: Does the type of diet significantly affected the body weight of mice at confidence levels of 95% and 99 %? Compare between group I and II.

  4. Solution For I, σ2=25 For II, σ2=68.75 For III, σ2=63.75

  5. = 1316.66 dfB= h-1= 3-1= 2 MSB= SSB/dfB= 658.33

  6. = 472.5 dfW= N-h= 12-3= 9 MSW= SSW/dfW= 52.5

  7. F0.05 (2, 9)= 4.26 F0.01 (2, 9)= 8.02

  8. f-distribution Table

  9. Tukey’s HSD (Honestly significance difference) Post-hoc test Number of groups = number of means Total number of Samples The critical value for comparison between two averages Critical q value (tabulated) Sample size /group

  10. Tukey’s HSD (Honestly significance difference) Post-hoc test Q= 3.95 (3.62)=14.31 -= 7.5 <Q (14.31) insignificant

  11. N (total sample size)- g (number of groups) g (3) 12– 3= 9

  12. The data below represent the levels of blood glucose before and after injection with a certain herbal extract. Did the herbal extract cause increased blood glucose levels??

  13. d.f. = n - 1 ttabulated at d.f. 5 = 2.015 tCal(12.84) > ttabulated(2.015) Significant, P<0.05 =12.84

  14. In an experiment to study the effect of pH value on the hepatic Cd content, the data below were recorded. Test the claim that Cd content at pH 8 is significantly higher than at pH 5?

  15. d.f.= n1 + n2 - 2 = 7+11 -2= 16 =15.73 =12

  16. = = 1.001 ttabulated at d.f. (7+11-2) = 1.746 tCal (1.001) < ttabulated(1.746) Insignificant, P>0.05

  17. t-distribution Table

More Related