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Chapter 12 – Simple Machines. A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University. © 2007.

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chapter 12 simple machines

Chapter 12 – Simple Machines

A PowerPoint Presentation by

Paul E. Tippens, Professor of Physics

Southern Polytechnic State University

© 2007

slide2

SIMPLE MACHINES are used to perform a variety of tasks with considerable efficiency. In this example, a system of gears, pulleys, and levers function to produce accurate time measurements.

Photo Vol. 1 PhotoDisk/Getty

objectives after completing this module you should be able to
Objectives: After completing this module, you should be able to:
  • Describe a simple machine in general terms and apply the concepts of efficiency, energy conservation, work, and power.
  • Distinguish by definition and example between the concepts of the ideal and actual mechanical advantages.
  • Describe and apply formulas for the mechanical advantage and efficiency of the following devices: (a) levers, (b) inclined planes, (c) wedges, (d) gears, (e) pulley systems, (f) wheel and axel, (g) screw jacks, and (h) the belt drive.
a simple machine

In a simple machine, input work is done by the application of a single force, and the machine does output work by means of a single force.

Fin

A simple machine

sin

Win= Finsin

sout

Fout

W

Wout= Foutsout

A Simple Machine

Conservation of energy demands that the work input be equal to the sum of the work output and the heat lost to friction.

a simple machine cont

Fin

Fin

Fin

A simple machine

sin

Win= Finsin

sout

Fout

Fout

W

W

Wout= Foutsout

A Simple Machine (Cont.)

Input work = output work + work against friction

Efficiency eis defined as the ratio of work output to work input.

slide6

Fin = ?

A simple machine

sin

Efficiency

sout

W

W

The advantage is a reduced input force, but it is at the expense of distance. The input force must move a greater distance.

sin = 5.0m

Example 1.The efficiency of a simple machine is 80% and a 400-N weight is lifted a vertical height of 2 m. If an input force of 20 N is required, what distance must be covered by the input force?

The efficiency is 80% or e = 0.80, therefore

power and efficiency

Fin = ?

A simple machine

sin

Efficiency

sout

W

W

Efficiency is the ratio of the power output to the power input.

Power and Efficiency

Since power is work per unit time, we may write

example 2 a12 hp winch motor lifts a 900 lb load

Fin = ?

A simple machine

sin

First we must find the power output, Po:

Efficiency

sout

W

W

Po = 6270 ftlb/s

Example 2.A12-hp winch motor lifts a 900-lb load

to a height of 8 ft. What is the output power in ftlb/s if the winch is 95% efficient?

Po= (0.95)(12 hp) = 11.4 hp

(1 hp = 550 ft/s):

ex 2 cont a12 hp winch motor lifts a 900 lb load

Fin = ?

A simple machine

sin

Efficiency

sout

W

W

Ex. 2 (cont.)A12-hp winch motor lifts a 900 lb load

to a height of 8 ft. How much time is required if the winch is 95% efficient?

We just found that Po = 6270 W

Now we solve for t :

Time required: t = 1.15 s

actual mechanical advantage

Fin = ?

A simple machine

sin

Actual Mechanical Advantage

Fout

sout

W

W

MA

40 N

80 N

Actual Mechanical Advantage

The actual mechanical advantage, MA, is the ratio of Fo to Fi.

For example, if an input force of 40 N lifts an 80 N weight, the actual mechanical advantage is:

an ideal machine

Conservation of energy demands that:

Input work = output work + work against friction

Anidealor perfect machine is 100% efficient and (Work)f = 0, so that

An Ideal Machine

The ratio si/sois the ideal mechanical advantage.

ideal mechanical advantage

Fin = ?

6 m

A simple machine

sin

Ideal Mechanical Advantage

2 m

Fout

sout

W

W

MI

Ideal Mechanical Advantage

The ideal mechanical advantage,MI, is the ratio of sin to sout.

For example, if an input force moves a distance of 6 m while the output force moves 2 m, the ideal mechanical advantage is:

efficiency for an ideal engine

IDEAL EXAMPLE:

Fin = 80 N

A simple machine

Sin = 8 m

Fout=400 N

Sout= 2 m

W

W

e = 100%

Efficiency for an Ideal Engine

For 100% efficiency MA = MI. In other words, in the absence of friction, the machine IS an ideal machine and e = 1.

efficiency for an actual engine

The efficiency of any engine is given by:

Efficiency for an Actual Engine

The actual efficiency is always less than the ideal efficiency because friction always exits. The efficiency is still equal to the ratio MA/MI.

In our previous example, the ideal mechanical advantage was equal to 4. If the engine was only 50% efficient, the actual mechanical advantage would be 0.5(4) or 2. Then 160 N (instead of 80 N) would be needed to lift the 400-N weight.

the lever

Fout

A lever shown here consists of input and output forces at different distances from a fulcrum.

rout

rin

Fin

Fulcrum

The input torque Firi is equal to the output torque Foro.

The actual mechanical advantage is, therefore:

The Lever
the lever16

Friction is negligible so that Wout = Win:

Fout

rout

sin

q

rin

q

sout

Fin

Note from figure that angles are the same and arc length sis proportional to r. Thus, the ideal mechanical advantage is the same as actual.

The idealMIis:

The Lever
slide17

800 N

ri

r2

Fo = 700 N; r2 = 20 cm

F = ?

r1 = 100 cm - 20 cm = 80 cm

Thus,

and

Example 3.A 1-m metal lever is used to lift a 800-N rock. What force is required at the left end if the fulcrum is placed 20 cm from the rock?

1. Draw and label sketch:

2. List given info:

3. To find Fi we recall the definition of MI :

For lever:MA = MI

wheel and axel

Application of Lever Principle:

With no friction MI = MAand

For Wheel and Axel:

R

Fi

r

Fo

Wheel and Axel

Wheel and Axel:

For example, if R = 30 cm and r = 10 cm, an input force of only 100 N will lift a 300-N weight!

If the smaller radius is 1/3 of the larger radius, your output force is 3 times the input force.

single fixed pulleys

Fin

Fout

Fout

Fin

W

Single Fixed Pulleys

Single fixed pulleys serve only to change the direction of the input force. See examples:

Fin = Fout

single moveable pulley

Fin

Fin

Fin

Fin + Fin = Fout

2 m

1 m

80 N

40 N + 40 N= 80 N

Fout

80 N

Note that the rope moves a distance of 2 m while the weight is lifted only 1 m.

Single Moveable Pulley

A free-body diagram shows an actualmechanical advantage of MA = 2 for a single moveable pulley.

block and tackle arrangement

Fi

Fi

Fi

Fi

Fi

Fo

Fo

The lifter must pull 4 m of rope in order to lift the weight 1 m

W

Block and Tackle Arrangement

We draw a free-body diagram:

the belt drive

Fo

ro

Since torque is defined as Fr, the ideal advantage is:

Belt Drive

ri

Fi

Belt Drive:

The Belt Drive

A belt drive is a device used to transmit torque from one place to another. The actual mechanical advantage is the ratio of the torques.

angular speed ratio

Do

wo

wi

Belt Drive

Di

Belt Drive:

Speed ratio:

Angular Speed Ratio

The mechanical advantage of a belt drive can also be expressed in terms of the diameters D or in terms of the angular speeds w.

Note that the smaller pulley diameter always has the greater rotational speed.

slide25

Fo

MI = 4

ro

To find Do we use the fact that

ri

Fi

Example 4.A 200 Nm torque is applied to an input pulley12 cm in diameter. (a) What should be the diameter of the output pulley to give an ideal mechanical advantage of 4? (b) What is the belt tension?

Do = 4(12 cm) = 48 cm

Now, ti = Firi and ri = Di/2. Belt tension is Fi and ri is equal to ½Di = 0.06 m.

gears

Gears:

No

Ni

In this case, Dois the diameter of the driving gear and Diis diameter of the driven gear. N is the number of teeth.

If 200 teeth are in the input (driving) gear, and 100 teeth in the output (driven) gear, the mech-anical advantage is ½.

Gears

Mechanical advantage of gears is similar to that for belt drive:

slide27

No = 20

Ni = 40

Example 5.The driving gear on a bicycle has 40 teeth and the wheel gear has only 20 teeth. What is the mechanical advantage? If the driving gear makes 60 rev/min, what is the rotational speed of the rear wheel?

Remember that the angular speed ratio is opposite to the gear ratio.

Output angular speed:

wo = 120 rpm

wo = 2wi = 2(60 rpm)

the inclined plane

Ideal Mechanical Advantage

The Inclined Plane

si

Fi

so

q

Fo = W

The Inclined Plane

Because of friction, the actual mechanical advantage MAof an inclined plane is usually much less than the ideal mechanical advantage MI.

slide29

Si = 8 m

Fi

2 m

q

Fo = 400 N

Example 6. An inclined plane has a slope of 8 m and a height of 2 m. What is the ideal mechan-ical advantage and what is the necessary input force needed to push a 400-N weight up the incline? The efficiency is 60 percent.

Fi = 167 N

the screw jack

An application of the inclined plane:

Fo

Input distance: si = 2pR

Fi

R

Output distance: so = p

p

Screw Jack

The Screw Jack

Due to friction, the screw jack is an inefficient machine with an actual mechanical advantage significantly less than the ideal advantage.

summary for simple machines

Efficiency eis defined as the ratio of work output to work input.

Efficiency is the ratio of the power output to the power input.

Summary for Simple Machines
summary

Fin = ?

A simple machine

The actual mechanical advantage, MA, is the ratio of Fo to Fi.

sin

Efficiency

sout

W

W

The ideal mechanical advantage,MI, is the ratio of sin to sout.

Summary
summary cont

Application of lever principle:

With no friction MI = MA

For Wheel and axel:

The actual mechanical advantage for a lever:

Summary (Cont.)
summary cont34

Fo

MI = 4

ro

ri

Fi

Belt Drive:

Belt Drive

Belt Drive:

Summary (Cont.)
summary35

Gears:

No

Ni

The Inclined Plane

Ideal Mechanical Advantage

si

Fi

so

q

Fo = W

Summary
summary cont36

An application of the inclined plane:

Fo

Input distance: si = 2pR

Fi

R

Output distance: so = p

p

Screw Jack

Summary (Cont.)