Calculation of Energy Performance of Buildings  Lithuanian Case Dr. Jurate Karbauskaite, dr. Edmundas Monstvilas, prof. V.Stankevicius, Institute of Architecture and Construction, Kaunas Technology University, Lithuania Building Energy Efficiency in the Baltics
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Calculation of Energy Performance of Buildings  Lithuanian CaseDr. Jurate Karbauskaite, dr. Edmundas Monstvilas, prof. V.Stankevicius, Institute of Architecture and Construction, Kaunas Technology University, Lithuania
Building Energy Efficiency in the Baltics
(BENEFIT2006), Riga, 25 October, 2006
At the point of view of longterm energy policy, the buildings ought to conform to the minimal requirements of energy performance in them in respect to the local climate.
The factors which serve to the growth of energy efficiency, must be taken into advantage
The biggest part in environment pollution is formed by heating of buildings
(IEA data)
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Comparison of energy consumption in Lithuania building stock with the European trends
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Energy consumption for heating during the recent 19972001 has been decreased by 15  20 %. In big apartment buildings mean energy consumption value can be assumed as 145 240 kWh/m2 at 3790 degree days at indoor air temperature of 18 °C.
Energy consumption in a big part, about 30 % of them, is significantly lower, mainly due to lowered indoor temperature, as well as other 30 % are consuming more than mean value. .
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
The National Building Code STR 2.01.09.2005 (BUILDING TECHNICAL REGULATION) BUILDING ENERGY PERFORMANCE CERTIFICATION states, that building energy efficiency is assessed only by calculation of the building energy consumption according to the method presented in the obligatory Annex.
Character of the tenants behavior and
state of the building envelope are not taken into consideration in recent normative document
Development in this direction shall be provided in the future stage
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
The energy performance is evaluated by classification indicator value,
which shall bedeterminated for a considered building due to the
total building normative QN.sum, reference QR.sum and calculated Qsumvalues
of building energyconsumption for 1 m2 of buildingheated area.
classification indicator valueis expressed by equation:
,
if
if
in the other cases
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
The performance class, depending on the value of the classification indicator C :
 Class A, if C 0,5;
 Class B, if 0,5 C 1;
 Class C, if 1 C 1,5;
 Class D, if 1,5 C 2;
 Class E, if 2 C 2,5;
 Class F, if 2,5 C 3;
 Class G, if C 3.
THE BUILDINGS COULD BE ATTRIBUTED TO ONE OF THE 7CLASSES:
A.B, C, D, E, F, G.
CLASS A IS AT THE TOP AND SUCH A BUILDING IS VERY ENERGY EFFICIENT WITH LOW ENERGY CONSUMPTION IN IT.
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Heating season values
Heat losses through the external walls;
Heat losses through roof;
Heat losses through building ceilings, which are in contact with external air;
Heat losses through building ceilings over unheated basement and crawls;
Heat losses through building elements on ground;
Heat losses through the windows;
Heat losses through external doors, excluding the heat losses due the door opening;
Heat losses through thermal bridges in building;
Heat losses due to opening of external door
Transmission heat losses
Heat losses due to door opening
Ventilation heat losses
Heat losses due overinfiltration of external air through windows

Solar heat gains
Internal heat gains
Domestic hot water supply (annual value)
Building energy
performance components
Electricity (annual value)
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Layout of basic heat losses in the residential buildings according to the construction year
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
The calculated efficiency factor of the mechanical ventilation system with heat recovery r
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Calculation of the heat losses because of extra normative infiltration of external air through windows and external doors
Normative heat lossesQN.inf. (kWh/(m2per year)) during the heating season because of extra normative infiltration of external air through windows and external doors, is set, that there should be no higher infiltration of external air than it’s needed for the ventilation of the building, so QN.inf.=0.
Reference QR.inf. (kWh/(m2per year)) heat losses during the heating season because of extra normative infiltration of external air through windows and external doors shall be calculated with respect to new and old window and door amount according to the equations in the Annex 2 of the Regulation.
Calculated Qinf(kWh/(m2per year)) heat losses during the heating season because of extra normative infiltration of external air through windows and external doors shall be calculated with respect to new and old window and door amount according to the equations in the Annex 2 of the Regulation.
BENEFIT2006, Riga, 25 October, 2006
Calculation of the heat losses through the external door due to doors opening
The heat losses Qd1 (kWh/(m2year)) during the heating season through the external door due to door opening shall be calculated according to the equation:
Calculation of Energy Performance of Buildings  Lithuanian Case
Calculation of the heat losses through the external door due to doors opening
The heat losses Qd1 (kWh/(m2 per year)) during the heating season through the external door due to door opening shall be calculated according to the equation:
where: Ao – the area for one occupant (m2). Selected from table 2.4;
kd1 – the correction coefficient, evaluating the frequency of opening of external doors of different types of the buildings, selected from table 2.11 of the Regulation.
kd2 – the correction coefficient, evaluating the type of external doors. The value of the coefficient shall be selected from table 2.12 of the Regulation with respect to the type of the external doors: according to the door, that is most frequently used or according to the door, that generalized corresponds to all types of external doors of the building;
h – the height of the building (m). That is the distance from the ground level to the highest point of the heated room, located at the upper part of the building.
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Correction coefficient for the doors kd1
Correction coefficient for the doors kd2
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Calculation of energy use for domestic hot water
Annual energy use for hot water Qh.w.(kWh/(m2per year)):
The efficiency factor of the hot water supply system h.w.
where:
ψh.w.– the annual energy demand for hot water per unit of the building area (kWh/(m2per year)). Selected from table 2.4;
h.w. – the efficiency factor of the hot water supply system. Selected from table 2.4.
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Calculation of sum energy consumption of the building
Normative sum QN.sum. (kWh/(m2per year)), reference sum QR.sum. (kWh/(m2 per year)) and calculated sum Qsum(kWh/(m2per year)) :
; ( )
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Casec
The calculated efficiency factor of the heat source 2
Calculated efficiency factor of the temperature control devices of the heating system 1
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Casec
Normative N.h.s. and reference Rh.s. heating system efficiency factors, different types of buildings
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Energy consumption layout for 5story apartment building
BENEFIT2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings  Lithuanian Case
Calculation program window with the part of input data and calculation results.
Building data:
Destination – residential
Heated area 175,22 m2
Height – 4,2 m
Walls, windows, doors by facades:
External door description
DHW supply system gas heater
Energy consumption – 213,76
Classification indicator value – 0,80
Energy performance class  B
BENEFIT2006, Riga, 25 October, 2006