Here Are Mind-Blowing Tricks To Check Divisibility Rules!!

1. Here Are Mind-Blowing Tricks To Check Divisibility Rules!! Are you stuck in tough calculations? Try these awesome divisibility rules to solve the questions five times faster. The divisibility rule is the technique that is used to make time-intensive calculations easier. It is an easy process of identifying the divisibility of any number without going through the conventional division process. If you are preparing for SSC, Bank PO, IBPS, UPSC CDS, or any other one-day competitive examination, then the divisibility rule will prove a boon for you. Students of class 10 can also learn this technique and refer to NCERT Solution for class 10 math. What if I ask you to find the factorization of 50811. If you know divisibility, you will easily crack the factorization of the given number. But, if you don’t know, it will be head scratching for you. There is plenty of use of divisibility in the domain of calculation.

2. Best Important Divisibility Rules to Make your Calculations Easier. Divisibility Rule by 2 If the number's last digit is even(2,4,6,8…etc.) or the unit digit is divisible by two, then the number is always divisible by 2. For example, 504, 674, 946, and 674 are always divisible by two because all the numbers have even numbers at their last position. But 303, 701, and 503 are not divisible by two because the last digit of the given numbers is not divisible by two. Exercise Identify the numbers divisible by 2 and answer the following in the comment box. 234, 205, 348, 1008, 1027, 5648, 7836, 341, 789, 3458. Divisibility Rule by 3 Any number whose sum of its digits is divisible by three is divisible by 3. For example- 453 To check the divisibility of 453, the sum of the digits should be divisible by 3. 4+5+3 = 12 12 is divisible by three; hence the number 453 is divisible by 3. Let us take more examples. 4056 Sum of the digit = 4+0+5+6 = 15

3. 15 is divisible by 3 so the 4056 is divisible by 3. 9835 Sum of the digits = 9+8+3+5 = 25 25 is not divisible by three; then the 9835 is not divisible by 3. Identify the numbers divisible by 3 and answer the following in the comment box. 567, 689, 3099, 678, 556, 777 Divisibility Rule by 4 If the last two digits of the numbers are divisible by four, then the number will always be divisible by 4. For example- 364 The last two digits = 364 64/4 = 16 The last two digits of the number should divisible by 4. Hence the number will be divisible by 4. 435 The last two digits = 435 35 is not divisible by 4. Hence the 435 is not divisible by 4. Identify the numbers divisible by 4 and answer the following in the comment box. 464, 658, 636, 788, 564, 231, 548

4. Divisibility Rule by 5 Numbers having the last digit(0 or 5) are divisible by 5. For example- 305 5 is the unit digit of the given number. Hence the number is divisible by 5. 2670 0 is the unit digit of the given number, so the number will always be divisible by 5. Find the numbers divisible by five and answer the following in the comment box. 335, 5670, 453, 455, 6530 Divisibility Rule by 6 A number is always divisible by 6 when it is divisible by 2 & 3. For example- 180, 258, 156, 1056. Also Read- NCERT Solution for class 9. Divisibility Rule by 7 Follow the step-by-step guide to check the divisibility of the number by 7. ● Remove the last digit of the given number. ● Double the number. ● Subtract it from the remaining given number. ● If the outcome is divisible by 7, then the number is divisible by 7 ● If not, then repeat the same process. For example- 203

5. Remove the last digit and double the number. 3 then 3 2 = 6 × Subtract from the remaining number 20 6 = 14 − 14 is divisible by 7. Hence 203 will be divisible by 7. Find the divisibility of given number and mention the answer below in comment section. 357, 294, 567, 445, 234 Divisibility Rule by 8 If the last three digits of the number is divisible by 8 then the number will always be divisible by 8. For example- 448 Last three digits of the numbers is divisible by 8 448/8 = 56 Hence the number is divisible by 8. Find the numbers divisible by 8 and answer the following in the comment box. 456, 788, 2456, 896 Divisibility by 9 Any number whose sum of its digits is divisible by nine will always be divisible by 9. For example- 9279 Sum of the digits of the given number- 9+2+7+9 = 27 27 is divisible by 9. Hence the number is divisible by 9 3456 Sum of the digits- 3+4+5+6 = 18

6. 18 is divisible by 9, so the number is divisible by 9. Find the numbers divisible by 8 and answer the following in the comment box. 9981, 6543, 4567, 67347 Divisibility Rule by 11 If the difference between the sum of digits of an even place and the odd place is “0” or divisible by “11,” it should always be divisible by 11. For example- 5824 5 8 2 4 O E O E Sum of odd place 5+2 = 7 Sum of even place 8+4 = 12 Difference 12 - 7 = 5 Five is not divisible by 11. Hence the number will not be divisible by 11. Take another example 8998 8 9 9 8 O E O E Sum of odd place 8+9 = 17

7. Sum of even place 8+9 = 17 Difference 17 - 17 = 0 8998 is divisible by 11. Identify the numbers divisible by 11 and answer the following in the comment box. 1001, 456, 572, 683 Conclusion The exam is nothing but proper planning. In the competitive world, one mistake can disqualify you from an examination. Mastering calculation skills lead you ahead in the competition. Learn divisibility to solve the questions rapidly. I hope you have found this blog very helpful. If you want to get out, most of us visit our website. Content Source- https://amazefeeds.com/here-are-mind-blowing-tricks-to-check-di visibility-rules/