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# Angles - PowerPoint PPT Presentation

R. S. Angles. Angle  is the ratio of two lengths: R: physical distance between observer and objects [km] S: physical distance along the arc between 2 objects Lengths are measured in same “units” (e.g., kilometers)

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Presentation Transcript

S

Angles

• Angle  is the ratio of two lengths:

• R: physical distance between observer and objects [km]

• S: physical distance along the arc between 2 objects

• Lengths are measured in same “units” (e.g., kilometers)

•  is “dimensionless” (no units), and measured in “radians” or “degrees”

R

R

“Angular Size” and “Resolution”

• Astronomers usually measure sizes in terms of angles instead of lengths

• because the distances are seldom well known

Y

S

R

Trigonometry

S = physical length of the arc, measured in m

Y = physical length of the vertical side [m]

Y

S

R

Definitions

• 2 ( 6.28) radians in a circle

• 1 radian = 360º 2p 57º

•   206,265 seconds of arc per radian

• Angular degree (º) is too large to be a useful angular measure of astronomical objects

• 1º = 60 arc minutes

• 1 arc minute = 60 arc seconds [arcsec]

• 1º = 3600 arcsec

• 1 arcsec  (206,265)-1 5  10-6 radians = 5 mradians

Y

S

R

Usually R >> S, so Y  S

sin[]  tan[]   for   0

Three curves nearly match for x  0.1 p|x|< 0.1p  0.314 radians

Check it!

18° = 18°  (2p radians per circle)  (360° per circle)

Calculated Results

tan(18°)  0.32

sin (18°) 0.31

0.314  0.32  0.31

 tan[] sin[] for | |<0.1

fist subtends angle of  5°

spread between extended index finger and thumb  15°

Easy yardstick: the Moon

diameter of disk of Moon AND of Sun  0.5° = ½°

½°  ½· 1/60 radian  1/100 radian  30 arcmin = 1800 arcsec

Astronomical Angular “Yardsticks”

• Real systems cannot “resolve” objects that are closer together than some limiting angle

• “Resolution” = “Ability to Resolve”

• Reason: “Heisenberg Uncertainty Relation”

• Fundamental limitation due to physics

1. Source emits “spherical waves”

2. Lens “collects” only part of the sphere

and “flips” its curvature

D

3. “piece” of sphere converges to

form image

Lens “collects” a smaller part of sphere.

Can’t locate the equivalent position (the “image”) as well

Creates a “fuzzier” image

Fuzzy Images “Overlap”

and are difficult to distinguish

(this is called “DIFFRACTION”)

Apparent angular separation of the stars is 

• Larger lens:

• collects more of the spherical wave

• better able to “localize” the point source

• makes “smaller” images

• smaller  between distinguished sources means BETTER resolution

• = wavelength of light

D = diameter of lens

• Better resolution with:

• larger lenses

• shorter wavelengths

• Need HUGE “lenses” at radio wavelengths to get the same resolution

• = wavelength of light

D = diameter of lens

• Can distinguish shapes and shading of light of objects with angular sizes of a few arcminutes

• Rule of Thumb: angular resolution of unaided eye is 1 arcminute

• Telescopes magnify distant scenes

• Magnification = increase in angular size

• (makes  appear larger)

• Simple refractor telescope (as used by Galileo, Kepler, and their contemporaries) has two lenses

• objective lens

• collects light and forms intermediate image

• “positive power”

• Diameter D determines the resolution

• eyepiece

• acts as “magnifying glass”

• forms magnified image that appears to be infinitely far away

fobjective

Ray incident “above” the optical axis

emerges “above” the axis

image is “upright”



Ray entering at angle  emerges at angle  > 

Larger ray angle  angular magnification

feyelens

fobjective

Ray incident “above” the optical axis

emerges “below” the axis

image is “inverted”



Ray entering at angle  emerges at angle 

where ||> 

Larger ray angle  angular magnification

• Ray trace for refractor telescope demonstrates how the increase in magnification is achieved

• Seeing the Light, pp. 169-170, p. 422

• From similar triangles in ray trace, can show that

• fobjective = focal length of objective lens

• feyelens = focal length of eyelens

• magnification is negative  image is inverted

• To increase apparent angular size of Moon from “actual” to angular size of “fist” requires magnification of:

• Typical Binocular Magnification

• with binoculars, can easily see shapes/shading on Moon’s surface (angular sizes of 10's of arcseconds)

• To see further detail you can use small telescope w/ magnification of 100-300

• can distinguish large craters w/ small telescope

• angular sizes of a few arcseconds

• Astronomical Unit (AU)

• distance from Earth to Sun

• 1 AU  93,000,000 miles  1.5 × 108 km

• light year = distance light travels in 1 year

• 1 light year

• = 60 sec/min  60 min/hr  24 hrs/day  365.25 days/year  (3  105) km/sec

•  9.5  1012 km  5.9  1012 miles  6 trillion miles

Apparent Position of Foreground

Star as seen from Location “B”

A

“Background” star

Foreground star

Earth’s Orbit

B (6 months later)

Apparent Position of Foreground

Star as seen from Location “A”

Aside: parallax and distance

• Only direct measure of distance astronomers have for objects beyond solar system is parallax

• Parallax: apparent motion of nearby stars against background of very distant stars as Earth orbits the Sun

• Requires images of the same star at two different times of year separated by 6 months

• P is the “parallax”

• typically measured in arcseconds

• Gives measure of distance from Earth to nearby star (distant stars assumed to be an “infinite” distance away)

P

Background star

Image from “A”

Image from “B” 6 months later

1"

R

Foreground star

Definition of Astronomical Parallax

• “half-angle” of triangle to foreground star is 1"

• Recall that 1 radian = 206,265"

• R = 206,265 AU  2×105 AU  3×1013 km

• 1 parsec  3×1013 km  20 trillion miles  3.26 light years

• R = P-1

• R is the distance (measured in pc) and P is parallax (in arcsec)

• Star with parallax (half angle!) of ½" is at distance of 2 pc  6.5 light years

• Star with parallax of 0.1" is at distance of 10 pc  32 light years

• SMALLER PARALLAX MEANS FURTHER AWAY

• Can you use a telescope to increase angular size of nearest star to match that of the Sun?

• nearest star is  Cen (alpha Centauri)

• Diameter is similar to Sun’s

• Distance is 1.3 pc

• 1.3 pc  4.3 light years  1.51013 km from Earth

• Sun is 1.5  108 km from Earth

•  would require angular magnification of 100,000 = 105

•  fobjective=105  feyelens

• BUT: you can’t magnify images by arbitrarily large factors!

• Remember diffraction!

• Diffraction is the unavoidable propensity of light to change direction of propagation, i.e., to “bend”

• Cannot focus light from a point source to an arbitrarily small “spot”

• Increasing magnification involves “spreading light out” over a larger imaging (detector) surface

• Diffraction Limit of a telescope

• BUT: atmospheric effects typically dominate diffraction effects

• most telescopes are limited by “seeing”: image “smearing” due to atmospheric turbulence

• Rule of Thumb:

• limiting resolution for visible light through atmosphere is equivalent to that obtained by a telescope with D˚˚3.5" ( 90 mm)