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Chapter 1 Chemistry and Measurements

Chapter 1 Chemistry and Measurements. 1.9 Problem Solving. Given and Needed Units. To solve a problem, identify the given unit identify the needed unit Example : A person has a height of 2.0 meters. What is that height in inches?

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Chapter 1 Chemistry and Measurements

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  1. Chapter 1 Chemistry and Measurements 1.9 Problem Solving

  2. Given and Needed Units To solve a problem, • identify the given unit • identify the needed unit Example: A person has a height of 2.0 meters. What is that height in inches? The given unitis the initial unit of height. given unit = meters (m) The needed unitis the unit for the answer. needed unit = inches (in.)

  3. Study Tip: Problem Solving Using GPS The steps in the Guide to Problem Solving (GPS) are useful in setting up a problem with conversion factors.

  4. Setting Up a Problem How many minutes are in 2.5 hours? Solution: Step 1 State the given and needed quantities. Given unit: 2.5 hours Needed unit: min Step 2Write a unit plan. Plan: hours min

  5. Solving a Problem How many minutes are in 2.5 hours? Step 3State equalities and conversion factors to cancel units. 60 min = 1 h 60 min and 1 h 1 h 60 min Step 4 Set up problem to cancel units. Given Conversion Needed unit unit factor 2.5 h x 60 min = 150 min (2 SF) 1 h

  6. Learning Check A rattlesnake is 2.44 m long. How many centimeters long is the snake?

  7. Solution A rattlesnake is 2.44 m long. How many centimeters long is the snake? Step 1 State the given and needed quantities. Given unit: 2.44 m Needed unit: cm Step 2Write a unit plan. Plan: meters centimeters

  8. Solution A rattlesnake is 2.44 m long. How many centimeters long is the snake? Step 3State equalities and conversion factors to cancel units. 1 m = 102 cm 102 cm and 1 m 1 m 102 cm Step 4 Set up problem to cancel units. Given Conversion Needed unit unit factor 2.44 m x 102 cm = 244 cm (3 SF) 1 m

  9. Learning Check How many minutes are in 1.4 days?

  10. Solution How many minutes are in 1.4 days? Step 1 State the given and needed quantities. Given unit: 1.4 days Needed unit: minutes Step 2Write a unit plan. Factor 1 Factor 2 Plan: days h min

  11. Solution How many minutes are in 1.4 days? Step 3State equalities and conversion factors to cancel units. 1 day = 24 hours 24 hours and 1 day 1 day 24 hours 1 hour = 60 minutes 60 min and 1 h 1 h 60 min

  12. Solution How many minutes are in 1.4 days? Step 4 Set up problem to cancel units. Given Conversion Conversion Needed unit unit factor factor 1.4 days x 24 h x 60 min = 2.0 x 103 min 1 day 1 h (rounded) 2 SF Exact Exact =2 SF

  13. Study Tip: Check Unit Cancellation • Be sure to check the unit cancellation in the setup. • The units in the conversion factors must cancel to give the correct unit for the answer. What is wrong with the following setup? 1.4 day x 1 day x 1 h 24 h 60 min = day2/min is not the unit needed. Units don’t cancel properly.

  14. Learning Check If your pace on a treadmill is 65 meters per minute, how many minutes will it take for you to walk a distance of 7.5 kilometers?

  15. Solution If your pace on a treadmill is 65 meters per minute, how many minutes will it take for you to walk a distance of 7.5 kilometers? Step 1 State the given and needed quantities. Given units: 7.5 km, 65 meters per minute Needed unit: minutes Step 2Write a unit plan. Factor 1 Factor 2 Plan: kilometers meters min

  16. Solution If your pace on a treadmill is 65 meters per minute, how many minutes will it take for you to walk a distance of 7.5 kilometers? Step 3State equalities and conversion factors to cancel units. 1 kilometer = 103 meters 103 meters and 1 kilometer 1 kilometer 103 meters 65 meters = 1 minute 65 meters and 1 minute 1 minute 65 meters

  17. Solution If your pace on a treadmill is 65 meters per minute, how many minutes will it take for you to walk a distance of 7.5 kilometers? Step 4 Set up problem to cancel units. Given Conversion Conversion Needed unit unit factor factor 7.5 kilometers x 103 meters x 1 minute = 120 minutes 1 kilometer 65 meters (rounded) 2 SF Exact 2 SF =2 SF

  18. Percent Factor in a Problem If the thickness of the skin fold at the waist indicates 11% body fat, how much fat is in a person with a mass of 86 kg? Percent factor: 11 kg fat 100 kg mass percent factor 86 kg mass x 11 kg fat 100 kg mass = 9.5 kg of fat

  19. Learning Check How many pounds of sugar are in 120 g of candy if the candy is 25% (by mass) sugar?

  20. Solution How many pounds of sugar are in 120 g of candy if the candy is 25% (by mass) sugar? Step 1 State the given and needed quantities. Given units: 120 g of candy 25% by mass sugar Needed unit: pounds sugar Step 2Write a unit plan. Conversion Percent factor factor Plan: grams pounds candy pounds sugar

  21. Solution How many pounds of sugar are in 120 g of candy if the candy is 25% (by mass) sugar? Step 3State equalities and conversion factors to cancel units. 1 pound = 454 grams 454 g and 1 lb 1 lb 454 g 25 pounds of sugar = 100 pounds of candy 25 lb sugar and 100 lb candy 100 lb candy 25 lb sugar

  22. Solution How many pounds of sugar are in 120 g of candy if the candy is 25% (by mass) sugar? Step 4 Set up problem to cancel units. Given Conversion Percent unit factor factor 120 g candy x 1 lb candy x 25 lb sugar 454 g candy 100 lb candy = 0.066 lb of sugar

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