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Hypergeometric Distribution. Example*: Automobiles arrive in a dealership in lots of 10. Five out of each 10 are inspected. For one lot, it is know that 2 out of 10 do not meet prescribed safety standards.

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hypergeometric distribution
Hypergeometric Distribution
  • Example*:

Automobiles arrive in a dealership in lots of 10. Five out of each 10 are inspected. For one lot, it is know that 2 out of 10 do not meet prescribed safety standards.

What is probability that at least 1 out of the 5 tested from that lot will be found not meeting safety standards?

*from Complete Business Statistics, 4th ed (McGraw-Hill)

slide2
This example follows a hypergeometric distribution:
    • A random sample of size n is selected without replacement from N items.
    • k of the N items may be classified as “successes” and N-k are “failures.”
  • The probability associated with getting x successes in the sample (given k successes in the lot.)

Where,

k = number of “successes” = 2 n = number in sample = 5

N = the lot size = 10 x = number found

= 1 or 2

hypergeometric distribution1
Hypergeometric Distribution
  • In our example,

= _____________________________

expectations of the hypergeometric distribution
Expectations of the Hypergeometric Distribution
  • The mean and variance of the hypergeometric distribution are given by
  • What are the expected number of cars that fail inspection in our example? What is the standard deviation?

μ =___________

σ2 =__________ , σ =__________

your turn
Your turn …

A worn machine tool produced defective parts for a period of time before the problem was discovered. Normal sampling of each lot of 20 parts involves testing 6 parts and rejecting the lot if 2 or more are defective. If a lot from the worn tool contains 3 defective parts:

  • What is the expected number of defective parts in a sample of six from the lot?
  • What is the expected variance?
  • What is the probability that the lot will be rejected?
binomial approximation
Binomial Approximation
  • Note, if N >> n, then we can approximate this with the binomial distribution. For example:

Automobiles arrive in a dealership in lots of 100. 5 out of each 100 are inspected. 2 /10 (p=0.2) are indeed below safety standards.

What is probability that at least 1 out of 5 will be found not meeting safety standards?

  • Recall: P(X≥ 1) = 1 – P(X< 1) = 1 – P(X = 0)
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