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Spring Benchmark Review: Part 2

Spring Benchmark Review: Part 2. LO- Students will review for part 2 of the spring benchmark What is the value of 3 x 3 + 2 x 2 − 4x when x = 2?. Write an expression that is equivalent to 4x + 2(8 + 2x). The equivalent expression should have only two terms.

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Spring Benchmark Review: Part 2

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  1. Spring Benchmark Review: Part 2 LO- Students will review for part 2 of the spring benchmark What is the value of 3x3+ 2x2 − 4x when x = 2?

  2. Write an expression that is equivalentto 4x + 2(8 + 2x). • The equivalent expression should have only two terms. • Rewrite the expression 4x + 2(8 + 2x) • LO- Students will review for spring benchmark

  3. Joe finds the perimeter of the square by finding the product of Thelength of the sides. S Catherine finds the perimeter of the square by finding the sum of the length of the sides. S S S Write an expression that represents each way the Perimeter was found. Who was correct?

  4. Line segment LO is one side of parallelogram LMNO What are the coordinates of O? If line segment NO passes through the y axis at its Exact middle,Where are the coordinates of N? Using coordinates of N how Can you find M?

  5. Part A • A large ice cream cone at Scoops is $3.00 • Any additional topping is $0.50 • Write an expression that can be used to find the cost of an ice cream cone with “t” toppings How many toppings 3.00 + (.50 × t) Cost of the ice cream Cost of topping

  6. Part B • If Jen orders an ice cream cone with 4 toppings, how much will it cost? Answer: 3.00 + (.50 × t) = 3.00 + (.50 × 4) = 3.00 + 2.00 = $5.00 A cone with 4 toppings will cost Jen $5.00

  7. Part C • Mike orders 3 ice cream cones. The first cone has an unknown number of toppings, t. The second cone has2 more toppings than the first, and the third cone has 4 more toppings than the first. Write an expression to find the cost of the ice cream cones Mike orders. First Cone $3.00 + ($.50)t $3.00 + ($.50)(t + 2) $3.00 + ($.50)(t + 4) Second Cone Third Cone $3.00 + ($.50)t + $3.00 + ($.50)(t + 2) + $3.00 + ($.50)(t + 4)

  8. Write an expression that is equivalent to the expression in Part C • 3.00 + .50t + 3.00 + .50t + 1.00 + 3.00+ .50t +2.00 • 12.00 +1.50t $3.00 + ($.50)t + $3.00 + ($.50)(t + 2) + $3.00 + ($.50)(t + 4)

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