Nonregular Languages. Section 2.4 Wed, Oct 5, 2005. Countability of the Set of DFAs. Theorem: The set of all DFAs (over an alphabet ) is countable. Proof: For a given n > 0, let S n be the set of all DFAs with exactly n states. How many DFAs are in S n ?
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Wed, Oct 5, 2005