LP CHNG EM TRN TRNG
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LỚP CHÚNG EM TRÂN TRỌNG KÍNH CHÀO CÁC THẦY CÔ PowerPoint PPT Presentation


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LỚP CHÚNG EM TRÂN TRỌNG KÍNH CHÀO CÁC THẦY CÔ. VD1: Nhieät ñoä T( ) taïi caùc thôøi ñieåm t (giôø) trong cuøng moät ngaøy ñöôïc cho trong baûng sau:. t(giôø). 0. 4. 8. 12. 16. 20. T( ). 20. 18. 22. 26. 24. 21. Tieát 29 : HAØM SOÁ. 1. Moät soá ví duï veà haøm soá:.

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LỚP CHÚNG EM TRÂN TRỌNG KÍNH CHÀO CÁC THẦY CÔ

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L p ch ng em tr n tr ng k nh ch o c c th y c

LP CHNG EM TRN TRNG

KNH CHO CC THY C


L p ch ng em tr n tr ng k nh ch o c c th y c

VD1: Nhiet o T( ) tai cac thi iem t (gi) trong cung mot ngay c cho trong bang sau:

t(gi)

0

4

8

12

16

20

T( )

20

18

22

26

24

21

Tiet 29:HAM SO

1. Mot so v du ve ham so:


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

VD 2: Khoi lng m(g) cua mot thanh kim loai ong chat co khoi lng rieng la 7,8 (cm ) t le thuan vi the tch V ( cm ) theo cong thc: m = 7,8.V

?1: Tnh gia tr tng ng cua m khi V = 1; 2; 3; 4 .

th m = 7,8 .1

7,8.

Vi V =1

=

Vi V =2th m = 7,8 .2= 15,6.

Vi V =3th m = 7,8 .3= 23,4.

Vi V =4th m = 7,8 .4 = 31,2.


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

VD3:

Thi gian t(h) cua mot vat chuyen ong eu tren quang ng 50 km t le nghch vi van toc v(km/h) cua no theo cong thc:

v(km/h)

5

10

25

50

?2: Tnh va lap bang cac gia tr tng ng cua t khi v = 5; 10; 25; 50

10

5

2

1


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

VD1: Nhiet o T( ) tai cac thi iem t (gi) trong cung mot ngay c cho trong bang sau:

t(gi)

0

4

8

12

16

20

T( )

20

18

22

26

24

21

Ta thay:

- Nhiet o T phu thuoc vao s thay oi cua thi gian t (gi).

- Vi moi gia tr cua t ta luon xac nh c ch mot gia tr tng ng cua T.

Ta noi: T la ham so cua t.


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

VD 2: Khoi lng m(g) cua mot thanh kim loai ong chat co khoi lng rieng la 7,8 (cm ) t le thuan vi the tch V (cm ) theo cong thc: m = 7,8.V

Vi V =1th m = 7,8 .1= 7,8.

Vi V =2th m = 7,8 .2= 15,6.

Vi V =3th m = 7,8 .3= 23,4.

Vi V =4th m = 7,8 .4= 31,2.

Ta thay:

- Khoi lng mcua thanh kim loai phu thuoc vao the tch V cua no.

- Vi moi gia tr cua V ta ch xac nh c mot gia tr tng ng cua m.

Ta noi: m la ham so cua V.


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

VD3:

Thi gian t(h) cua mot vat chuyen ong eu tren quang ng 50 km t le nghch vi van toc v(km/h) cua no theo cong thc:

v(km/h)

5

10

25

50

10

5

2

1

Ta thay:

-Thi gian t phu thuoc vao van toc v.

- Vi moi gia tr cua v ta ch xac nh c mot gia tr tng ng cua t.

Ta noi: t la ham so cua v.


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

2 . Khai niem ham so:

Neu ai lng y phu thuoc vao ai lng thay oi x sao cho vimoi gia tr cua xta luon xac nhch mot gia tr tng ng cua y th y cgoi laham so cua x va x goi labien so.

e y la ham so cua x can co cac ieu kien sau ay:

- x va y eu nhan cac gia tr so.

- ai lng y phu thuoc vao ai lng x.

- Vi moi gia tr cua x ch co mot gia tr tng ng cua y.


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

2 . Khai niem ham so:

Bai toan: Hai ai lng x va y c cho trong bang sau:

x

1

2

3

4

y

2

2

2

2

Hoi ai lng y co la ham so cua ai lng x khong?

Neu ai lng y phu thuoc vao ai lng thay oi x sao cho vimoi gia tr cua xta luon xac nhch mot gia tr tng ng cua y th y cgoi laham so cua x va x goi labien so.


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

2 . Khai niem ham so:

Neu ai lng y phu thuoc vao ai lng thay oi x sao cho vimoi gia tr cua xta luon xac nhch mot gia tr cua y th y cgoi laham so cua x va x goi labien so.

Chu y:

+ Khi x thay oi ma y luon nhan mot gia tr th y c goi laham hang.

  • + Ham so co the c cho bang bang (nh trong VD1), bang cong thc (nh trong VD2, VD3).

+ Khi y la ham so cua x ta co the viet y = f(x); y = g(x);

VD: Ham soy = 2x + 3ta co the viety = f(x) = 2x + 3 .

Khi o, thay cho cau khi x bang 3 th gia tr tng ng cua ybang 9 ta vietf(3) = 9 .


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

2 . Khai niem ham so:

Bai 24: Cac gia tr tng ng cua hai ai lng x va y c cho trong bang sau:

ai lng y co phai la ham so cua ai lng x khong?

x

-4

-3

-2

-1

1

2

3

4

y

16

9

4

1

1

4

9

16

ai lng y la ham so cua ai lng x v :

+ ai lng y phu thuoc vao ai lng x.

+ Vi moi gia tr cua x ch co mot gia tr tng ng cua y.

Giai


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

2 . Khai niem ham so:

Bai 35b (SBT): ai lng y co la ham so cua ai lng x khong, neu bang cac gia tr tng ng cua chung la:

x

4

4

9

16

y

-2

2

3

4

Giai

y khong phai la ham so cua x v ng vi x = 4 co hai gia tr tng ng cua y la (-2) va 2.


L p ch ng em tr n tr ng k nh ch o c c th y c

Tiet 29:HAM SO

1. Mot so v du ve ham so:

2 . Khai niem ham so:

Bai 25: Cho ham so y = f(x) = . Tnh: f ; f(1) ; f(3).

f

f(1) =

f(3) =

Giai

=

=

=


L p ch ng em tr n tr ng k nh ch o c c th y c

HNG DN V NH:

- Nam vng khai niem ham so.

- Lam cac bai tap 26, 27, 28 (SGK trang 64).


L p ch ng em tr n tr ng k nh ch o c c th y c

TRAN TRONG KNH CHAO


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