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Here is that in-class problem reprised plus, a second example.PowerPoint Presentation

Here is that in-class problem reprised plus, a second example.

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As mentioned Wednesday, Oct. 15

as we worked out in detail a simple AC series RLC circuit:

"This is EXACTLY the kind of problem you’ll find on your NEXT quiz!"

Here is that in-class problem reprised plus, a second example.

You should review your notes from that day’s class, as well as

Section 24.5 and the associated assigned problems:

Ch.24: P 47, 49, 51

A series RLC circuit has a resistance

of 25.0, a capacitance of 50.0mF,

and an inductance of 0.300 H. If

driven by a 120v, 60Hz source, find:

(a) the impedance of the circuit.

(b) the current in the circuit.

(c) the phase angle between current and voltage.

(d) the rms voltage drop across each component.

(e) the power dissipated in the circuit.

XL=113.1

XC= 53.1

Z = 65

1.85 A

+76.3o

VR=46.25v

VL=209v

VC=98.24v

85.67 Watts

(f) What fwould make this circuit completely resistive?

(g) What would the power dissipated in the resistor be then?

41 Hz

576 Watts

A series RLC circuit has a resistance

of 250 , a capacitance of 3.50 mF,

and an inductance of 0.600 H. If

driven by a 150v, 60Hz source, find:

(a) the impedance of the circuit.

(b) the current in the circuit.

(c) the phase angle between current and voltage.

(d) the rms voltage drop across each component.

(e) the power dissipated in the circuit.

XL=226.2

XC=757.9

Z = 587.5

0.255 A

-64.8o

VR=63.8v

VL=57.6v

VC=193v

16.28 Watts

(f) What fwould make this circuit completely resistive?

(g) What would the power dissipated in the resistor be then?

109.8 Hz

90 Watts

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