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## PowerPoint Slideshow about ' EE 241 Design Problem' - yates

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Specifications

- Typical Lab Supply
- Single Output
- Flyback converter in DCM
- Vi = universal supply (85V to 264V)
- Io = 0 to 3A
- Vo = 2V to 20V

Flyback Converter

- Assumptions:
- Efficiency = 80%
- fs = 175kHz
- Iout = 5A

- Design Approach
- 5 Outputs (4.3V, 8.3V, 12.3V, 16.3V, 20.3V)
- Tap Configuration

- 15V Primary Auxiliary Output
- To power PWM Controller

- 24V Secondary Auxiliary Output
- To power op-amps in linear regulator and the flyback switcher

- 5 Outputs (4.3V, 8.3V, 12.3V, 16.3V, 20.3V)

Flyback Transformer Design

- Primary Side:
- Core: E14-3C90
- Ie = 78.6mm, Ae = 97.1mm^2, Ue =67

(1)

N = 26.68 turns

- Secondary Side:

(2)

15V flyback auxiliary output: Nsec = 3.48 turns

24V flyback auxiliary output: Nsec = 4.93 turns

Flyback Transformer

- Secondary Side:
- Multi-output tap configuration
- Outputs are in 4V increments (4.3V, 8.3V, 12.3V, 16.3V, 20.3V)
- Eq. 2 is used to get Nsec for Vout = 4.3V
- Nsec(4.3V) = 0.998 turns
- Nsec(4V) = 0.938 turns
- Nsec(8.3V) = Nsec(4.3V) + Nsec(4V)
- Nsec(12.3V) = Nsec(4.3V) + 2*Nsec(4V)
- Nsec(16.3V) = Nsec(4.3V) + 3*Nsec(4V)
- Nsec(20.3V) = Nsec(4.3V) + 4*Nsec(4V)

Flyback Transformer

- PWM Controller Circuit and Switch:
- Osc pin:
- fs = 175kHz, 1.8/RC, R >= 5kHz
- R1 = 5kohms, C4 = 2nF

- Sense pin:
- Pout = Vout,max*Iout,max = 20.3*5A=101.5W
- I_peak = (5.5*Pout)/Vin,min = (5.5*101.5)/(85*sqrt(2))
= 4.64A

- Rsense = 1.0/I_peak = 1.0/4.64 = 215mΩ

- Osc pin:

Flyback Transformer

Flyback (PWM Controller)

Flyback (Simulation)

- Conditions: Vin = 85Vrms

Flyback (Simulation)

- Conditions: Vin = 85Vrms

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