5687134
This presentation is the property of its rightful owner.
Sponsored Links
1 / 35

По праву достойна в стихах быть воспета о свойствах корней … PowerPoint PPT Presentation


  • 163 Views
  • Uploaded on
  • Presentation posted in: General

По праву достойна в стихах быть воспета о свойствах корней …. ТЕОРЕМА ВИЕТА. ?. Цели урока:. воспроизведение раннее изученных знаний и способов действий; их применение в разных формах работы, в заданиях различной сложности; проверка уровня усвоения знаний по данной теме. Сформулируйте

Download Presentation

По праву достойна в стихах быть воспета о свойствах корней …

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript


5687134


5687134


5687134

?


5687134

:

  • ;

  • , ;

  • .


5687134

.


5687134

: , ,


5687134

,


5687134

, :

, g, 1 , 2,

, q,

1, 2 :


5687134

.

1 = 2 , 2 = 4

6

8

1 = -1 , 2 = -4

- 5

4


5687134

6, 5.

2 + px + q = 0

x1 + x2 = - p

x1 x2 = q

1) - 6 + 5 = 0

2) - 6 - 5= 0

) + 6 + 5= 0

4) + 6 - 5 = 0


5687134

, 1 2

3

-70

- 3-70 = 0

10

24

- 10 + 24= 0


1 3 2 4 px q 0

1 = - 3 2 = - 4 + px + q = 0,

2 + px + q = 0

x1 + x2 = - p

x1 x2 = q

1) p = - 7, q = 12

2) p = 12, q = 7

) p = 7, q = 12

4) p = - 7, q = -12

5) p = 12, q = - 7


6 72 0

- 6 72 = 0

2 + px + q = 0

x1 + x2 = - p

x1 x2 = q

1) 1 + 2 = - 6, 1 2= -72

2) 1+ 2 = -72, 1 2= - 6

) 1 + 2 = 6, 1 2= -72

4) 1 + 2 = 6, 1 2= 72


5687134

:

d(-24): 1 -24;

2 -12;

3 - 8;

4 - 6;

6 -4;

8 -3;

12 -2;

24 -1.

x2 - 10x -24 = 0

x2 8x + 12 = 0

x1 +x2 = 10

x1 x2 = -24

d(12): 1 12;

2 6;

3 4.

x1 + x2 = 8

x1x2 = 12


5687134

:

1) 2 + 2012 2013 = 0

2) 2 +2013 +2012 = 0


5687134

, , :

1) 2 + 9 + 18 = 0, 1 = -6

2) 2 17 + 60 = 0, 1 =12


5687134

?

,

ax + b + = 0, = 0


5687134

, .

ax + b + = 0, = 0

x + b/a x + c/a = 0

:

1 + 1 = - b/a

1 1 = c/a


5687134

, :

, , ?

, :

, .

.

,

, .

c

b

a


5687134

( )

: 5 - 5;

4 - 4;

3 - 3.


5687134

:

.29

455 (2,4,6,),

456 (2,4,6),

465, 466 ( ),

( ).

!


5687134

  • , .

  • .

  • , .

  • .


5687134

?

?


5687134

55-68

1 ,

2 .


5687134

:

  • ...

  • ...

  • ...


5687134

:

,

.

, ,

.

,

, ,

.


5687134

.


  • Login