H 0 298
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∆H 0 298 PowerPoint PPT Presentation


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∆H T. ∆H 0 298. Reactants. Products. (T). (T). ∆H products = Σ C p (298-T) =- Σ C p (T-298). ∆H reactant = Σ C p (T-298). Reactants. Products. fuel, 상온. [products + H 2 O (g) ]. [products + H 2 O (l) ]. dq. dq = Higher Heating Value = │-∆H L │. Cooling. O 2.

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∆H 0 298

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H 0 298

∆HT

  • ∆H0298

Reactants

Products

(T)

(T)

∆Hproducts=ΣCp(298-T)

=-ΣCp(T-298)

∆Hreactant=ΣCp(T-298)

Reactants

Products


H 0 298

  • fuel, 상온

[products + H2O(g)]

[products + H2O(l)]

dq

dq = Higher Heating Value

= │-∆HL│

Cooling

O2

dq = Lower Heating Value

= │-∆Hg│

미국

우리나라, 중동

HHV = LHV + [latent heat, heat of vaporization]

* Latent heat = 44,000J/mole = 9712 Kcal/Kgmole → table 2-3 p.17


H 0 298

*Cp(°K기준):


H 0 298

  • ex 2-7) Energy Balance

  • 성분; C6H6 : 70% Excess air : 10%

  • C : 8.2% Preheating air : 300°C

  • Ash : 9.3% Heat loss : 5%

  • H2O : 12.5% Burning rate : 1100Kg/hr

Air(300°C)

5% Heat loss

5% Heat loss

Combustion

Chamber

Combustion

Chamber

Waste

(1100Kg/hr)

Water

100°C

Steam

(15.8atm)

180°C

Ash

100 Kg of Waste 를 기준,

C6H6 : 70% → 70Kg/78 = 0.897Kgmole, C : 8.2% → 0.683 Kgmole

Ash : 9.3%, H2O : 12.5% → 0.694 Kgmole

0.897C6H6 + 0.683C + (1.1)x(O2 + 3.76N2)

→ 6.065CO2 + 2.691H2O + 0.1xO2 + (1.1x)(3.76)N2

For O2, 1.1xO2 = 6.065 + 1.345 +0.1x, x = 7.41

0.897C6H6 + 0.683C + (1.1)(7.14)(O2 + 3.76N2)

→ 6.065CO2 + 2.691H2O + 0.714O2 + (8.151)(3.76)N2


H 0 298

  • * 총 수분배출 mole수 : (2.691 + 0.694) Kgmoles/100Kg of waste

  • * Dry gas moles : 6.065 + 0.741 + (8.151)(3.76)

  • = 37.5Kgmole/100Kg of waste

  • *시간당 배출되는 dry gas : (37.5Kgmole/100Kg of waste)(1100Kg/hr)

  • = 41.25 Kgmole/hr


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