1 / 18

11.2 Probability Day 1

11.2 Probability Day 1. 5/3/16 Tuesday. Warm – up #2 5/3/16. Work on Extra W-S Counting Principle . (one sided) I will stamp Friday 4/29, when finished. Today: Notes Pg. 5-7. Yesterday: Notes Pg. 3-4. Homework Log. 5/3/16 Lesson 11-2 Probability Day 1. Pg. 5-7 Notes packet.

wwelch
Download Presentation

11.2 Probability Day 1

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 11.2 Probability Day 1 5/3/16 Tuesday

  2. Warm – up #2 5/3/16 Work on ExtraW-S Counting Principle. (one sided) I will stamp Friday 4/29, when finished. Today: Notes Pg. 5-7 Yesterday: Notes Pg. 3-4

  3. Homework Log

  4. 5/3/16 Lesson 11-2 Probability Day 1 Pg. 5-7 Notes packet Algebra II

  5. Pg. 5 Notes packet Probability P(Event) = P(E) Toss of coin: Probability of landing on heads: P(H) = “Probability of an event”

  6. Pg. 5 Notes packet Probability P(will definitely occur) = 1 ex: Have 1 die. P(roll a #) = 1 P(never occur) = 0 ex: Have 1 die. P(roll a letter) = 0

  7. Pg. 5 Notes packet Ex: EX: A die is rolled. Find the probability the number showing is even. Even: 2, 4 , 6  # of favorable outcomes = 3 # of total outcomes = 6 P(Even) = EX: A die is rolled. Find the probability the number showing is a 5 or a 6. # of favorable outcomes P(5 or 6) = = 2

  8. Pg. 6 Notes packet Probability EX: A spinner is divided into tenths. The sections are numbered 1 to 10. If the spinner is spun, find the probability the number is • a multiple of 4 4 or 8 P(4 or 8) = • between 0 and 30 1, 2, 3, 4, 5, …10 P(1, 2, … , 10) = 1 10 2 9 3 8 4 7 5 6

  9. Pg. 6 Notes packet Probability A spinner is divided into tenths. The sections are numbered 1 to 10. If the spinner is spun, find the probability the number is • 2 P(2) = • ½ ½ isn’t on the spinner P(½) = 1 10 2 9 3 8 4 7 5 6

  10. Pg. 6 Notes packet Probability EX: A bag contains 8 brown socks and 6 black socks. If two socks are randomly drawn, what is the probability that they will match? Total socks = 14 Two cases: 1. Two Brown: 2. Two Black: only 7 brown & 13 total left now OR only 5 black & 13 total left now

  11. Pg. 6 Notes packet Probability EX: A die is rolled. Find the probability of each event. • The number showing is less than 5 1, 2, 3, or 4 • The number showing is between 2 and 6. 3, 4, 5

  12. Pg. 6 Notes packet Probability EX: Two dice are rolled and the numbers are noted. Find the probability of each event. • The sum of the numbers is less than 5

  13. Pg. 7 Copy it down! Part a) Sum < 5 ? Possibilities when 2 dice are rolled TOTAL = 36

  14. Pg. 6 Notes packet Probability Two dice are rolled and the numbers are noted. Find the probability of each event. • The sum of the numbers is less than 5 • The sum of the numbers is 4 or 5.

  15. Part b) Sum = 4 or 5 ? Possibilities when 2 dice are rolled

  16. Back to Pg. 6 Notes packet Probability Two dice are rolled and the numbers are noted. Find the probability of each event. • The sum of the numbers is 4 or 5. P(4 or 5) =

  17. Probability EX: There are 12 tulip bulbs in a package. Nine will yield yellow tulips and three will yield red tulips. If two bulbs are selected at random, find the probability of each event. • Both tulips will be red • One tulip will be yellow and the other red CaseI: Y/R Case 2: R/Y 12 total 9 Yellow 3 Red only 2 red & 11 total left now

  18. Homework 15-9 Probability WS

More Related