How Tall Is It? 2011

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# How Tall Is It? 2011 - PowerPoint PPT Presentation

How Tall Is It? 2011. Maddie Wohlfarth Will Freeman Maryellen Newton Madeline Held. 30°. Tan= opp / adj Tan30=x/40 Tan30*40=x x≈23.09 . x. 30°. 40. Short leg= long leg / √3 40/√3=x 23.09=x. x + my height ( up to my eyes) = the height of the goal post 23.09+5=height of goal post.

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Presentation Transcript

### How Tall Is It?2011

Will Freeman

Maryellen Newton

30°

Tan30=x/40

Tan30*40=x

x≈23.09

x

30°

40

Short leg= long leg / √3

40/√3=x

23.09=x

x + my height ( up to my eyes) = the height of the goal post

23.09+5=height of goal post

• Goal post= 28.09 feet
45°

45°

x ft

Tan45=x/22

Tan45(22)=x

x=22 ft

45°

90°

22 ft

In a 45-45-90 Δ, leg=leg, so x=22 ft.

My height to my eyes≈5.58 ft

Height of the Goalpost≈27.58 ft

22 ft+5.58 ft=27.58 ft

60°

xft

x+my height ( up to my eyes)=the height of the goal post

24.25+4.8=height of goal post

Goal post=29.05

Tan60=x/14

Tan60*14=x

x=24.25

60°

Short leg=Long leg√3

14=x√3

x=14/√3

x=24.25

14 ft

20.52+5.25=height of goal post

Goal post=25.77

25°

Tan 25=

Tan 25=

x

x≈20.52

25°

44 ft.

Conclusion

We learned how to use geometry, trigonometry, and special right Δs in everyday life to solve for height and length based problems that can be used in architecture and design. Our average goal post height was 27.62.