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IPR 1

IPR 1. ME311 THERMAL-FLUIDS I DESIGN PROJECT BY CADETS: MICHAEL FARIES WILL PUNTENNEY SUSAN RICE BOB WALTERS. Purpose. Task Design a power plant to meet the Central Area power demands Goal

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IPR 1

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  1. IPR 1 ME311 THERMAL-FLUIDS I DESIGN PROJECT BY CADETS: MICHAEL FARIES WILL PUNTENNEY SUSAN RICE BOB WALTERS

  2. Purpose Task Design a power plant to meet the Central Area power demands Goal Determine whether it would be cheaper to continue to purchase electrical power from the local counties or to utilize the power plant to produce sufficient electrical power

  3. BASIC POWER PLANT DESIGN State 3: Pressure= 11 MPa Temperature= 596.2517 C Specific Enthalpy= 3606.89 kJ/kg Specific Entropy= 6.84 kJ/kg*K Mass Flow Rate= 12 kg/s State 2: Pressure= 11 MPa Temperature= 51.43 C Specific Enthalpy= 224.739 kJ/kg Specific Entropy= 0.7171 kJ/kg*K Mass Flow Rate= 12 kg/s State 4: Pressure= 1 MPa Temperature= 250 C Specific Enthalpy= 2942 kJ/kg Specific Entropy= 6.923 kJ/kg*K Mass Flow Rate= 12 kg/s State 1: Pressure= 0.101325 MPa Temperature= 51.16 C Specific Enthalpy= 214.27 kJ/kg Specific Entropy= 0.7187 kJ/kg*K Mass Flow Rate = 12 kg/s

  4. Turbine Analysis • Total Power Output= 7978.72 kW • (Power,gen)/(Generator Efficiency) • Mass Flow Rate= 12 kg/s • Given • Entropy Generation= 0.945 kJ/kg*K • S,gen=(mass flow rate)*(S4-S3)

  5. Pump Analysis • Required Power Input= 125.628 kW • (Power)=(mass flow rate)*(h2-h1)

  6. Boiler Analysis • Heat Transfer to Steam= 40585.85 kW • Heat in= (mass flow rate)*(h3-h2) • Heat Input by Fuel= 44216 MMBtu • Heat input of Fuel=(Heat transferred to steam)/(Boiler Efficiency) • Mass Flow Rate of Fuel= 0.895 kg/s • Mass flow rate= (Heat input by fuel)/ (higher heating value)

  7. IMPROVED POWER PLANT DESIGN

  8. Table 4: Design Matrix

  9. Questions?

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