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Metodický úvod (určenie konštanty α s ). Detektor DELPHI. SCHÉMA DETEKTORA VO FYZIKE ČASŤÍC. Identifikácia častíc. Rozpady Z 0 (10 -24 s). Pri E CMS =91 GeV e + e -  Z 0 Z 0  e + e - (3,67%) Z 0  μ + μ - (3,67%) Z 0  τ + τ - (3,67%) Z 0   qq ( 2 jety ) (60%)

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metodick vod ur enie kon tanty s
Metodický úvod

(určenie konštanty αs)

rozpady z 0 10 24 s

Rozpady Z0 (10-24s)

Pri ECMS=91 GeV e+e- Z0

Z0 e+e- (3,67%)

Z0 μ+μ- (3,67%)

Z0τ+τ- (3,67%)

Z0qq( 2 jety ) (60%)

Z0qq g( 3 jety ) (24%)

Z04 a viac jetov(6%)

slide8
e+e-Z0t+t-m+m-

častica tau sa rozpadne skôr,

než ju stihneme zaregistrovať

Tau častica sa rozpadá na:

t– -> nt + e– +net+ -> ne + e+ +nτv 17% prípadov

t– -> nt + m– +nmt+ -> nμ + m+ +nτv 17% prípadov

t– -> nt + hadróny t+ -> nt + hadróny v 60% prípadov

τ+τ– e+e- + 4 neutrína

τ+τ– μ+μ- + 4 neutrína

τ+τ– μ+e- + 4 neutrína

DELPHI

Z0 → τ+τ–
slide10

Z0 → τ+τ–

jeden tau sa rozpadol na elektrón a druhý na hadrón

slide13

DELPHI

Rozpad na kvark a antikvark:e+ e-→ Z0 → qq ggg ( s vyžiarením 3 gluónov )

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