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Chapter 5 Choice

Chapter 5 Choice. Economic Rationality. The principal behavioral postulate is that a decisionmaker chooses his most preferred alternative from those available to him. The available choices constitute the choice set. How is the most preferred bundle in the choice set located?.

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Chapter 5 Choice

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  1. Chapter 5Choice

  2. Economic Rationality • The principal behavioral postulate is that a decisionmaker chooses his most preferred alternative from those available to him. • The available choices constitute the choice set. • How is the most preferred bundle in the choice set located?

  3. Rational Constrained Choice x2 x1

  4. Rational Constrained Choice x2 Affordablebundles x1

  5. Rational Constrained Choice x2 More preferredbundles Affordablebundles x1

  6. Rational Constrained Choice x2 More preferredbundles Affordablebundles x1

  7. Rational Constrained Choice x2 (x1*,x2*) is the mostpreferred affordablebundle. x2* x1 x1*

  8. Rational Constrained Choice • The most preferred affordable bundle is called the consumer’s ordinary demand at the given prices and budget. • Ordinary demands will be denoted byx1*(p1,p2,m) and x2*(p1,p2,m).

  9. Rational Constrained Choice • When x1* > 0 and x2* > 0 the demanded bundle is interior. • If buying (x1*,x2*) costs $m then the budget is exhausted.

  10. Rational Constrained Choice x2 (x1*,x2*) is interior.(a) (x1*,x2*) exhausts thebudget; p1x1* + p2x2* = m. x2* x1 x1*

  11. Rational Constrained Choice x2 (x1*,x2*) is interior .(b) The slope of the indiff.curve at (x1*,x2*) equals the slope of the budget constraint. x2* x1 x1*

  12. Rational Constrained Choice • (x1*,x2*) satisfies two conditions: • (a) the budget is exhausted; p1x1* + p2x2* = m • (b) the slope of the budget constraint, -p1/p2, and the slope of the indifference curve containing (x1*,x2*) are equal at (x1*,x2*).

  13. Rational Constrained Choice • Condition (b) can be written as: • That is, • Therefore, at the optimal choice, the ratio of marginal utilities of the two commodities must be equal to their price ratio.

  14. Mathematical Treatment • The consumer’s optimization problem can be formulated mathematically as: • One way to solve it is to use Lagrangian method:

  15. Mathematical Treatment • Assuming the utility function is differentiable, and there exists an interior solution. • The first order conditions are:

  16. Mathematical Treatment • So, for interior solution, we can solve for the optimal bundle using the two conditions:

  17. Computing Ordinary Demands - a Cobb-Douglas Example. • Suppose that the consumer has Cobb-Douglas preferences. • Then

  18. Computing Ordinary Demands - a Cobb-Douglas Example. • So the MRS is • At (x1*,x2*), MRS = -p1/p2 so (A)

  19. Computing Ordinary Demands - a Cobb-Douglas Example. • So now we have • Solving these two equations, we have (A) (B)

  20. Computing Ordinary Demands - a Cobb-Douglas Example. • So we have discovered that the most preferred affordable bundle for a consumer with Cobb-Douglas preferences is

  21. A Cobb-Douglas Example x2 x1

  22. A Cobb-Douglas Example • Note that with the optimal bundle: • The expenditures on each good: • It is a property of Cobb-Douglas Utility function that expenditure share on a particular good is a constant.

  23. Special Cases

  24. Special Cases

  25. Some Notes • For interior optimum, tangency condition is only necessary but not sufficient. • There can be more than one optimum. • Strict convexity implies unique solution.

  26. Corner Solution • What if x1* = 0? • Or if x2* = 0? • If either x1* = 0 or x2* = 0 then the ordinary demand (x1*,x2*) is at a corner solution to the problem of maximizing utility subject to a budget constraint.

  27. Examples of Corner Solutions -- the Perfect Substitutes Case x2 MRS = -1 x1

  28. Examples of Corner Solutions -- the Perfect Substitutes Case x2 MRS = -1 Slope = -p1/p2 with p1 > p2. x1

  29. Examples of Corner Solutions -- the Perfect Substitutes Case x2 MRS = -1 Slope = -p1/p2 with p1 > p2. x1

  30. Examples of Corner Solutions -- the Perfect Substitutes Case x2 MRS = -1 Slope = -p1/p2 with p1 < p2. x1

  31. Examples of Corner Solutions -- the Perfect Substitutes Case • So when U(x1,x2) = x1 + x2, the most preferred affordable bundle is (x1*,x2*) where and if p1 < p2 if p1 > p2

  32. Examples of Corner Solutions -- the Perfect Substitutes Case x2 MRS = -1 Slope = -p1/p2 with p1 = p2. x1

  33. Examples of Corner Solutions -- the Perfect Substitutes Case x2 All the bundles in the constraint are equally the most preferred affordable when p1 = p2. x1

  34. Examples of Corner Solutions -- the Non-Convex Preferences Case x2 Better x1

  35. Examples of Corner Solutions -- the Non-Convex Preferences Case x2 x1

  36. Examples of Corner Solutions -- the Non-Convex Preferences Case x2 Which is the most preferredaffordable bundle? x1

  37. Examples of Corner Solutions -- the Non-Convex Preferences Case x2 The most preferredaffordable bundle x1

  38. Examples of Corner Solutions -- the Non-Convex Preferences Case x2 Notice that the “tangency solution” is not the most preferred affordable bundle. The most preferredaffordable bundle x1

  39. Examples of ‘Kinky’ Solutions -- the Perfect Complements Case x2 U(x1,x2) = min{ax1,x2} x2 = ax1 x1

  40. Examples of ‘Kinky’ Solutions -- the Perfect Complements Case x2 U(x1,x2) = min{ax1,x2} ¥ MRS = - MRS is undefined x2 = ax1 MRS = 0 x1

  41. Examples of ‘Kinky’ Solutions -- the Perfect Complements Case x2 U(x1,x2) = min{ax1,x2} x2 = ax1 x1

  42. Examples of ‘Kinky’ Solutions -- the Perfect Complements Case x2 U(x1,x2) = min{ax1,x2} Which is the mostpreferred affordable bundle? x2 = ax1 x1

  43. Examples of ‘Kinky’ Solutions -- the Perfect Complements Case x2 U(x1,x2) = min{ax1,x2} The most preferred affordable bundle x2 = ax1 x1

  44. Examples of ‘Kinky’ Solutions -- the Perfect Complements Case x2 U(x1,x2) = min{ax1,x2} x2 = ax1 x2* x1* x1

  45. Examples of ‘Kinky’ Solutions -- the Perfect Complements Case x2 U(x1,x2) = min{ax1,x2} (a) p1x1* + p2x2* = m(b) x2* = ax1* x2 = ax1 x2* x1* x1

  46. Examples of ‘Kinky’ Solutions -- the Perfect Complements Case (a) p1x1* + p2x2* = m; (b) x2* = ax1*. Solving the two equations, we have

  47. Examples of ‘Kinky’ Solutions -- the Perfect Complements Case x2 U(x1,x2) = min{ax1,x2} x2 = ax1 x1

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