V v 0 a t x v 0 t 1 2 a t 2 v 2 v 0 2 2a x
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v = v 0 + a ∆t ∆x = v 0 ∆t + 1/2 a∆t 2 v 2 = v 0 2 + 2a∆x - PowerPoint PPT Presentation


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v = v 0 + a ∆t ∆x = v 0 ∆t + 1/2 a∆t 2 v 2 = v 0 2 + 2a∆x. To create equations for freely falling bodies, simply replace a with g. v = v 0 + a ∆t ∆x = v 0 ∆t + 1/2 a∆t 2 v 2 = v 0 2 + 2a∆x. v = v 0 + g ∆t ∆x = v 0 ∆t + 1/2 g∆t 2 v 2 = v 0 2 + 2g∆x.

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V v 0 a t x v 0 t 1 2 a t 2 v 2 v 0 2 2a x
v = v0 + a ∆t∆x = v0∆t + 1/2 a∆t2v2 = v02 + 2a∆x



V v 0 a t x v 0 t 1 2 a t 2 v 2 v 0 2 2a x1
v = v replace 0 + a ∆t∆x = v0∆t + 1/2 a∆t2v2 = v02 + 2a∆x


V v 0 g t x v 0 t 1 2 g t 2 v 2 v 0 2 2g x
v = v replace 0 + g ∆t∆x = v0∆t + 1/2 g∆t2v2 = v02 + 2g∆x


When freely falling bodies start from rest v 0 0 so v g t x 1 2 g t 2 v 2 2g x
When freely falling bodies start from rest, v replace 0 = 0, so:v = g ∆t∆x = 1/2 g∆t2v2 = 2g∆x


These equations refer to a situation with constant acceleration due to gravity and no air resistance. Such motion is called free fall.


Example acceleration due to gravity and no air resistance. : A ball is dropped froma height of 10 meters. How long will it be in the air before it strikes the floor?


Example acceleration due to gravity and no air resistance. : A ball is thrown vertically upward with a velocity of 100 m/s. (a) To what height will it rise? (b) How long will it take for the ball to fall back to the earth?


Example a ball drops from rest and attains a velocity of 62 m s how much time has elapsed
Example acceleration due to gravity and no air resistance. : A ball drops from rest and attains a velocity of 62 m/s. How much time has elapsed?


Example how far did the ball in the previous problem fall during the third second
Example acceleration due to gravity and no air resistance. : How far did the ball in the previous problem fall during the third second?


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