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SISTEM KOORDINAT. Proyeksi. Koordinat X ( Bujur ). Koordinat Y ( Lintang ). X = 106 o 50’30” BT Y = 6 o 20’00 LS. X = 106 o 50’30” BT Y = 6 o 20’00 LS. 1 o = 60’ (1 Derajat = 60 Menit ) 1’ = 60” (1 Menit = 60 Detik ) 1 o = 60’x60’ = 360” (1 Derajat = 3600 Detik ) JADI

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Presentation Transcript
slide7

Koordinat X (Bujur)

Koordinat Y (Lintang)

x 106 o 50 30 bt y 6 o 20 00 ls1
X = 106o50’30” BTY = 6o20’00 LS
  • 1o = 60’ (1 Derajat = 60 Menit)
  • 1’= 60” (1 Menit = 60 Detik)
  • 1o = 60’x60’ = 360” (1 Derajat = 3600 Detik)

JADI

  • 50’ = 50/60 = 0.833o
  • (50 Menit = 0.833 Derajat)
  • 30” = 30/3600 = 0.00833o
  • (30 Detik = 0.00833 Derajat)
  • 50’30” = 0.833 + 0.00833 = 84133 o

X = 106,8413 o (Desimal Degree)

sistem proyeksi utm
SISTEM PROYEKSI UTM
  • Universal Transverse Mercator (UTM)
  • Untukmengetahui zone UTM
  • wilayah yang akanditransformasikan
  • digunakanrumus :
  • GarisBujur/6 + 30 = ZONE*

* Hasilnilai zone selaludibulatkankeatas (zone 49,1 ~ zone 50)

x 106 o 50 30 bt y 6 o 20 00 ls2
X = 106o50’30” BTY = 6o20’00 LS

Zona Utara

Lintang 0

Zona Selatan

Bujur Barat (BT)

Bujur Timur (BT)

106/6 +30 = 17,66 + 30 = 47,66 ~ 48

Y = 6o20’00 LS

Maka

Zona 48 South/Selatan

sistem koordinat tm3
Sistem Koordinat TM3
  • Penggunaansistemkoordinat yang dianggapakuratyaitu Transverse Mercator 3 yang lebihdikenalsebagaiSistemKoordinat TM3.
  • Sistemkoordinatinimemodifikasisistemkoordinat yang sudahadasebelumnyayaitu UTM WGS 1984,
  • DengancaramembagiSistemProyeksi UTM 6oke 3o
  • Sehingga dalam satu zona UTM 48 selatan misalnya, terdiri dari 2 zona TM3, yaitu TM3 zona 48.1 dan TM3 zona 48.2.
slide15

48 North

UTM

0O

48 South

102O

108O

114O

zone

48

50

49

1 Zone = 6 Derajat

48.1 N

48.2 N

TM3

0O

48.1 S

48.2 S

105O

108O

102O

106O30’

103O30’

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