1 / 24

Mrs. Rivas

Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Mrs. Rivas. Then substitute to answer the question. Mrs. Rivas. X = 3. = 4 (3) – 1. = 11. m ∠ AOB = 4 x – 1. m ∠ BOC = 2 x + 15. = 2 (3) + 15. = 21. 2x + 15. m ∠ AOC = 8 x + 8. = 8 (3) + 8. = 32.

trevet
Download Presentation

Mrs. Rivas

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Mrs. Rivas

  2. Mrs. Rivas

  3. Mrs. Rivas

  4. Mrs. Rivas

  5. Mrs. Rivas

  6. Mrs. Rivas

  7. Mrs. Rivas Then substitute to answer the question.

  8. Mrs. Rivas X = 3 = 4(3) – 1 = 11 m∠AOB = 4x – 1 m∠BOC = 2x + 15 = 2(3) + 15 = 21 2x + 15 m∠AOC = 8x + 8 = 8(3) + 8 =32 8x + 8 4x – 1

  9. Mrs. Rivas 3x – 10 8x + 13 Then substitute to answer the question.

  10. Mrs. Rivas X = 9 12x – 6 m∠COD = 8x + 13 = 8(9) + 13 = 85 = 3(9) – 10 = 17 m∠BOC = 3x – 10 3x – 10 8x + 13 =102 m∠BOD = 12x – 6 = 12(3) – 6

  11. Mrs. Rivas Always read the question and draw a picture. 3x + 8 = 2x + 48 – 8 – 8 3x = 2x + 40 – 2x – 2x x = 40 A E 3(40) + 8 = 128 2(40) + 48 = 128 B 3x + 8 2x + 48 F C

  12. Mrs. Rivas Always read the question and draw a picture. 2x– 3 + 5x+ 2 = 90º 2x – 3 + 5x + 2 = 90º 7x– 1 = 90º + 1 + 1 7x = 91º 5(13) + 2 = 67 J N 2x – 3 7 7 L 2(13) – 3 = 23 M x = 13º 5x + 2 K P

  13. Mrs. Rivas

  14. Mrs. Rivas

  15. Mrs. Rivas

  16. Mrs. Rivas

  17. Mrs. Rivas Always read the question and draw a picture. If ∠JKM = 86 then ∠MKL = 86, so ∠JKL has to be equal to 86+86 = 172. J M 86 K L

  18. Mrs. Rivas Always read the question and draw a picture. Since bisectmeans cut in half. Then, m∠RSV = 62 ÷ 2 = 31 62 R V S T

  19. Mrs. Rivas Always read the question and draw a picture. 3x= 5x – 20 – 5x – 5x – 2x= – 20 P 5x – 20 S 2 2 3x x= 10 Q 3(10) = 30 5(10) – 20 = 30 R So, m∠PQR= 30 + 30 = 60

  20. Mrs. Rivas Always read the question and draw a picture. 2x + 1 = 4x – 15 – 1 – 1 2x= 4x – 16 P – 4x – 4x 4x – 15 S 2x + 1 – 2x= – 16 Q 4(8) – 15 = 17 2(8) + 1 = 17 2 2 R So, m∠PQR= 17 + 17 = 34 x= 8

  21. Mrs. Rivas Always read the question and draw a picture. 30 + 30 = 3x – 12 60 = 3x – 12 + 12 + 12 30 P S 72 = 3x 3x –12 3 3 Q 3(24) – 12 = 60 R x= 24

  22. Mrs. Rivas Always read the question and draw a picture. 2x + 10 = 5x – 17 – 10 – 10 2x= 5x – 27 P – 5x – 5x 5x – 17 S 2x + 10 – 3x= – 27 Q 3 3 5(9) – 17 = 28 2(9) + 10 = 28 R x= 9 So, m∠PQR= 28 + 28 = 56

  23. Mrs. Rivas Always read the question and draw a picture. b). a). m∠MLN = 7(8) – 1 = 55 7x– 1 + 4x+ 3 = 90º 11x+ 2 = 90º m∠JKL = 4(8) + 3 = 35 – 2 – 2 c). I can check the answer by adding 55 and 35, and it should be 90º. 55 + 35 = 90º 11x= 88º 11 11 x= 8

  24. Mrs. Rivas

More Related