CHAPTER 9. Chemical Quantities. 9.1.
- First we balance the equation by dividing by two, resulting in H2O – H2 + ½ O2
- Then multiply each by 5.8, resulting in 5.8H2O – 5.8H2 + 2.9O2.
LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l)
2 mol LiOH
How much of each item would I need to make 40 sandwiches for the football team at their upcoming game?