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COMP541 Flip-Flop TimingPowerPoint Presentation

COMP541 Flip-Flop Timing

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COMP541 Flip-Flop Timing

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COMP541Flip-Flop Timing

Montek Singh

Oct 6, 2014

- Timing analysis
- flip-flops
- sequential systems
- clock skew

- Anyone having trouble with Lab 7?
- Be careful about the “Sync Polarity”
- A “1” means a downward going pulse
- sync signal is normally high, but goes low during the pulse

- A “0” means an upward going pulse

- A “1” means a downward going pulse
- Use my self-checking text bench!
- simulates my VGA driver …
- … and compares your outputs with mine
- flags any mismatches

Timing of sequential circuits

- Setup time: tsetup = time before the clock edge that data must be stable (i.e. not changing)
- Hold time: thold = time after the clock edge that data must be stable
- Aperture time: ta = time around clock edge that data must be stable(ta = tsetup + thold)

- Propagation delay: tpcq= max time after clock edge by which output Q is guaranteed to have stabilized (i.e., not changing anymore)
- Contamination delay: tccq= min time after clock edge during which Q will not have started changing yet

- The input to a synchronous sequential circuit must be stable during the aperture (setup and hold) time around the clock edge
- Specifically, the input must be stable
- at least tsetup before the clock edge
- at least until thold after the clock edge

- Constrains operation
- Given a clock period, constrains circuit delays
- Given a circuit, constraints clock period
- The delay between registers (which impacts clock period) has a minimum and maximum delay, dependent on the delays of the circuit elements

- Delays of both comb. logic and flip-flops must be taken into account

- Setup time
- input to R2 must be stable at least tsetup before the clock edge
- constrains max delay from R1 through combinational logic

- What’s min clock period?

What’s Tc?

Tc ≥ tpcq + tpd + tsetup

tpd ≤ Tc – (tpcq + tsetup)

- So, clock period constrained by:
- Delay in CL
- Delay in previous reg (R1)
- Setup requirement in next reg (R2)

- Hold time
- input to R2 must be stable for at least thold after clock edge
- constrains the minimum delay from register R1 through the combinational logic
- often try to design circuits with 0 hold time requirement

thold < tccq + tcd

tcd > thold - tccq

Timing Characteristics

tccq = 30 ps (FF contamination)

tpcq = 50 ps (FF propagation)

tsetup = 60 ps

thold = 70 ps

tpd = 35 ps

tcd = 25 ps

tpd =

tcd =

Setup time constraint:

Tc≥

fc =

tpd = 3 x 35 ps = 105 ps

tcd = 25 ps

Setup time constraint:

Tc≥ (50 + 105 + 60) ps = 215 ps

fc = 1/Tc = 4.65 GHz

Hold time constraint:

tccq + tcd > thold ?

(30 + 25) ps > 70 ps ? No!

Add buffers to the short paths:

Timing Characteristics

tccq = 30 ps

tpcq = 50 ps

tsetup = 60 ps

thold = 70 ps

tpd = 35 ps

tcd = 25 ps

tpd = 3 x 35 ps = 105 ps

tcd = 2 x 25 ps = 50 ps

Setup time constraint:

Tc≥ (50 + 105 + 60) ps = 215 ps

fc = 1/Tc = 4.65 GHz

Hold time constraint:

tccq + tpd > thold ?

(30 + 50) ps > 70 ps ? Yes!

- Often flip-flops are designed for a hold time of zero
- To avoid these tricky problems

- Clock doesn’t arrive at all registers at the same time
- Skew is the difference between the arrival times of the clock edge at two different (typically neighboring) flip-flops

- Examine the worst case:
- guarantee that discipline is not violated for anyregister pair
- many registers in a system!

Worst case: CLK2 is earlier than CLK1

Tc ≥ tpcq + tpd + tsetup + tskew

tpd ≤ Tc – (tpcq + tsetup + tskew)

- We won’t go over example
- Have a look in book

- Read Section 3.5.1-3.5.3
- Then we’ll move on to memories
- Section 5.5