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9. 2 C 3 H 7 OH + 9 O 2 → 6 CO 2 + 8 H 2 O PowerPoint PPT Presentation


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9. 2 C 3 H 7 OH + 9 O 2 → 6 CO 2 + 8 H 2 O. Identify some mole ratios, using the given equation for the combustion of isopropyl alchol. a) 6 mol CO 2 2 mol C 3 H 7 OH. d) 8 mol H 2 O 2 mol C 3 H 7 OH. b ) 2 mol C 3 H 7 OH 9 mol O 2. e ) 6 mol CO 2

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9. 2 C 3 H 7 OH + 9 O 2 → 6 CO 2 + 8 H 2 O

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9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

9. 2 C3H7OH + 9 O2 → 6 CO2 + 8 H2O

Identify some mole ratios, using the given equation for the

combustion of isopropyl alchol.

a)6 mol CO2

2 mol C3H7OH

d)8 mol H2O

2 mol C3H7OH

b)2 mol C3H7OH

9 mol O2

e)6 mol CO2

8 mol H2O

c)9 mol O2

6 mol CO2

f)8 mol H2O

9 mol O2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

Mole Ratios

3 CaCl2 + 2 H3PO4 → Ca3(PO4)2 + 6 HCl

Identify some mole ratios, using the given equation.

a)3 CaCl2 b) 6 HClc)3 CaCl2

1 Ca3(PO4)2 2 H3PO4 2 H3PO4

d)1 Ca3(PO4)2 e) 6 HClf)2 H3PO4

2 H3PO4 1 Ca3(PO4)2 6 HCl


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

11. C2H5OH + 3 O2→2 CO2 + 3 H2O

How many moles of CO2 can be produced from

7.75 molC2H5OH?

7.75 mol C2H5OH 2 mol CO2= 15.5 mol CO2

1 mol C2H5OH

or

2 mol CO2= X = 15.5 mol CO2

1 mol C2H5OH7.75 mol C2H5OH


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

4 HCl + O2→2 Cl2 + 2 H2O

How many moles of Cl2can be produced from

5.60 molHCl?

5.60 mol HCl2 mol Cl2 =2.80 mol Cl2

4 mol HCl

or

2 mol Cl2=X =2.80 mol Cl2

4 mol HCl 5.60 mol HCl


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

13. MnO2 + 4 HCl → Cl2 + MnCl2 + 2 H2O

How many moles of HCl will react with

1.05 mol MnO2?

1.05 mol MnO24 mol HCl = 4.20 mol HCl

1 mol MnO2

or

1.05 mol MnO2 = 1 mol MnO2

X mol HCl 4 mol HCl

X = 4.20 mol HCl


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

  • 14. Al4C3 + 12 H2O → 4 Al(OH)3 + 3 CH4

  • How many moles of water are needed to react with 100. g Al4C3 ?

  • How many moles of Al(OH)3 will be produced when 0.600 mol

  • of CH4 is formed?

100.0 g Al4C31 molAl4C312 mol H2O = 8.333 mol H2O

144.0g Al4C3 1 molAl4C3

0.600 mol CH4 4 mol Al(OH)3 = 0.800 mol Al(OH)3

3 mol CH4


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

15.

Ca(OH)2 + Na2CO3→ 2 NaOH+ CaCO3

How many grams of sodium hydroxide can be produced from

500 g of calcium hydroxide according to this equation?

1 mole Ca(OH) 2= 74.1 g Ca(OH) 2= 500 g

2 moles NaOH 80.0 g NaOHx

74.1 x = 40000 x = 540 g NaOH


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

How many grams of zinc phosphate, Zn3(PO4)2,

are formed when 10.0 g of Zn are reacted with

phosphoric acid?

3 Zn + 2 H3PO4 → Zn3(PO4)2 + 3 H2

10.0 g

? g

3 mol Zn

1 mol Zn3(PO4)2

= 196.2 g Zn

386.1 g Zn3(PO4)2

196.2 g Zn = 10.0 g Zn

386.1 g Zn3(PO4)2 X g Zn3(PO4)2

X = 19.7 gZn3(PO4)2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

17.

Fe2O3+ 3C → 2Fe + CO

How many kilograms of iron would be

formed from 125 kg of Fe2O3?

1 mole Fe2O3 = 0.1598 kg= 125 kg

2 mole Fe 0.1118 kg x

0.1598 x = 13.975

x = 13.975 = 87.5 kg Fe

0.1598


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

18.How many grams of steam and iron must react to

produce 375 g of magnetic iron oxide, Fe3O4?

3 Fe + 4 H2O → Fe3O4 + 4 H2

3 mol Fe

1 mol Fe3O4

=167.4 g Fe

231.6 g Fe3O4

=X g Fe

375 g Fe3O4

X = 271 g Fe

4 mol H2O

1 mol Fe3O4

=72.0 g H2O

231.6 g Fe3O4

=X g H2O

375 g Fe3O4

X = 117 g H2O


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

19. a.

2C2H6+ 7O2→ 4CO2 + 6H2O

How many moles of O2 are needed for the complete combustion

of 15.0 mol of ethane?

7 mole O2= X mole O2

2 mole C2H6 15 mole C2H6

2x = 105

x = 52.5 mole O2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

19 b.

2C2H6+ 7O2→ 4CO2 + 6H2O

How many grams of CO2are produced for each 8.00 g of H2O

produced?

4 mole CO2 = 176 g CO2 = Xg CO2

6 mole H2O 108 g H2O 8.00gH2O

108x = 1408

x = 1408 = 13.0 g CO2

108


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

19 c.

2C2H6+ 7O2 → 4CO2 + 6H2O

How many grams of CO2will be produced by the combustion of 75.0 g of C2H6?

4 mole CO2 = 2 = 88.0 g CO2 = x

2 mole C2H6 1 30.0g C2H6 75.0

30x = 6600

x = 6600 = 220. g CO2

30


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

20.4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2

How many moles of Fe2O3 can be made from

1.00 mol of FeS2 ?

4 mol FeS2

2 mol Fe2O3

= 1.00 mol FeS2

X mol Fe2O3

X = 0.500 mol Fe2O3


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

20.4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2

(b) How many moles of O2 are required to react with

4.50 mol of FeS2 ?

4 mol FeS2

11 mol O2

=4.50 mol FeS2

X mol O2

X = 12.4 mol O2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

20.4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2

(c) If the reaction produces 1.55 mol of Fe2O3 , how

many moles of SO2 are produced?

2 mol Fe2O3

8 mol SO2

= 1.55 mol Fe2O3

X mol SO2

X = 6.20 mol SO2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

20.4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2

(d) How many grams of SO2 can be formed from

0.512 mol of FeS2 ?

0.512 mol FeS2

8 mol SO2

4 mol FeS2

= 1.02 mol SO2

1.02 mol SO2

64.1 g SO2

1 mol SO2

= 65.4 g SO2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

20.4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2

(e) If the reaction produces 40.6 g of SO2 , how

many moles of O2 were reacted?

40.6 g SO2

1 mol SO2

64.1 g SO2

= 0.633 mol SO2

0.633 mol SO2

11 mol O2

8 mol SO2

= 0.870 mol O2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

20.4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2

(f) How many grams of FeS2 are needed to produce

221 g of Fe2O3 ?

221 g Fe2O3

1 mol Fe2O3

159.7 g Fe2O3

= 1.38 mol Fe2O3

1.38 mol Fe2O3

4 mol FeS2

2 mol Fe2O3

= 2.76 mol FeS2

2.76 mol FeS2

120.0 g FeS2

1 mol FeS2

= 331 g FeS2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

20.4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2

(f) How many grams of FeS2 are needed to produce

221 g of Fe2O3 ?

4 mol FeS2

2 mol Fe2O3

=480.0 g FeS2

319.4 g Fe2O3

= X g FeS2

221 g Fe2O3

X = 332 g FeS2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

22.

a)2 Bi(NO3)3 + 3 H2S → Bi2S3 + 6 HNO3

50.0 g 6.00 g ? g

2 Bi(NO3)3 = 790 g Bi(NO3)3 = 50.0 g Bi(NO3)3

1 Bi2S3 514.3 g Bi2S3 X grams Bi2S3

X = 32.6 grams

3 H2S = 102.3 g H2S = 6.00 g H2S

1 Bi2S3 514.3 g Bi2S3 X g Bi2S3

H2S limitsX = 30.2 grams


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

22.

b.) 3 Fe + 4 H2O → Fe3O4 + 4 H2

40.0 g 16.0 g ? grams

3Fe = 167.4 g Fe = 40.0 g Fe x= 1.91 g H2

4H2 8.0 g x g H2

4H2O = 1H2O = 18.0g H2O = 16.0 g H2O

4H2 1H2 2.0 g H2 x g H2

H2O limiting x= 1.78 g H2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

23) a)C3H8+ 5 O2 → 3 CO2 + 4 H2O

20.0 g 20.0 g ? mol

20.0 g C3H8 1 mol C3H8 3 mol CO2 = 1.36 mol CO2

44.0 g C3H8 1 mol C3H8

20.0 g O2 1 mol O2 3 mol CO2= 0.375 mol CO2

32.0 g O2 5 mol O2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

23 b)

C3H8+ 5 O2 → 3 CO2 + 4 H2O

20.0 g 80.0 g ? mol

20.0 g C3H8 1 mol C3H8 3 mol CO2 = 1.36 mol CO2

44.0 g C3H8 1 mol C3H8

80.0 g O2 1 mol O2 3 mol CO2 = 1.50 mol CO2

32.0 g O2 5 mol O2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

24.

C3H8 + 5O2 →3CO2 + 4H2O

5.0 mole 5.0 mole ? Moles

1C3H8 = 5C3H8 X = 15 mole CO2

3 CO2 X

5O2 = 5 X = 3.0 mole CO2

3CO2 X

O2 limits


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

24. C3H8 + 5O2 →3CO2 + 4H2O

3.0 mole 20. mole ? moles

b) 1 mole C3H8 = 3.0 C3H8

3 mole CO2 X

X = 9.00 mole CO2

C3H8 limits

5 mole O2 = 20. O2

3 mole CO2 XX = 12 mole CO2


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

24. C3H8 + 5O2 →3CO2 + 4H2O

3.0 mole 20. mole ? moles

24c)

1 C3H8 = 20 C3H8

3 CO2 X

X = 60 mol CO2

5 O2= 3 O2

3 CO2 X

X = 1.8 mol CO2

O2 limits


9 2 c 3 h 7 oh 9 o 2 6 co 2 8 h 2 o

27)

2 Al + 3 Br2 →2 AlBr3

25.0 g 100.0 g ? g

If 64.2 g of AlBr3 is recovered, what is the percent yield?

2 mol Al = 54.0 g Al = 25.0 g Al X = 247 g

2 mol AlBr3 533.4 g AlBr3 X g AlBr3

3 mol Br2 = 479.4 g Br2 = 100.0 g Br2 X = 111.3 g

2 mole AlBr3 533.4 g AlBr3 X g AlBr3

% yield = Actual (lab) x 100 = 64.2 g = 57.7 % Calculated (theory) 111.3 g


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