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Flashback 10-3-12

Flashback 10-3-12. In the figure below, < H < F ;  E ,  G , and  I  are collinear; and  G  is the midpoint of  FH . To prove that  HI FE  given the conditions stated above, which of the following is a logical order for the 5 steps in the table below? A.  1, 2, 3, 4, 5 B.  1, 2, 3, 5, 4

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Flashback 10-3-12

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  1. Flashback 10-3-12 In the figure below, <H<F; E, G, and I are collinear; and G is the midpoint of FH. To prove that HIFE given the conditions stated above, which of the following is a logical order for the 5 steps in the table below? A. 1, 2, 3, 4, 5 B. 1, 2, 3, 5, 4 C. 1, 2, 4, 3, 5 D. 1, 4, 2, 3, 5 E. 1, 5, 4, 2, 3

  2. Joke of the day He said I was average -

  3. but he was just being mean.

  4. Finding domain • Really finding what cannot be in the domain. • Ex. : f(x) = √(x + 3) • Think: What values would cause problems for us, assuming real number values? • Square root functions cannot have • So, • And the domain is

  5. Try this one • Domain of g(x) = (√x)/ (x – 5)

  6. How about this? • A(s) = (√3 /4) s2 where A(s) is the area of an equilateral triangle with side s.

  7. Range • F(x) = 2/x • What do you expect it to be? • Graph it. • What does the range appear to be? • How can we confirm?

  8. Continuity • A function is continuous if it has no gaps in the graph.

  9. Discontinuous functions Removable • discontinuity • Jump discontinuity Infinite discontinuity

  10. HW: p. 102 Ex. 5-12, 21-24

  11. Exit Slip p. 104 #84

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