# Chapter 10: Lesson 5 -Titration- - PowerPoint PPT Presentation

1 / 9

Chapter 10: Lesson 5 -Titration-. Need Right Combo To Create Balance. = + But which blue?. yellow. green. Titration. Uses neutralization to find concentration of acid or base Equivalence point is when acid balances base

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

Chapter 10: Lesson 5 -Titration-

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

#### Presentation Transcript

Chapter 10: Lesson 5

-Titration-

= +

But which blue?

yellow

green

### Titration

• Uses neutralization to

find concentration of

acid or base

• Equivalence point is

when acid balances base

and solution is a neutral pH of 7

### Moles H+ = Moles of OH-

• How many moles of HCl are needed to exactly neutralize 5 moles of NaOH?

• How many moles of LiOH are needed to exactly neutralize 2 moles of H2SO4?

### If Not Simple Mole #

MAVA = MBVB

• MAVA = concentration acid x volume acid

• MBVB = concentration base x volume base

• M =mol/L

### M = mol/L

• How many moles of HCl are needed to neutralize 0.1 L of 2 M solution of NaOH?

### MAVA = MBVB

• It takes 15 mL of 0.4 M NaOH to neutralize 5 mL of HCl. What is the concentration of the HCl?

### MAVA = MBVB

• How many mL of 0.1 M Ca(OH)2 are required to neutralize 25 mL of 0.5 M HNO3?

### For The Rest Of Class

• Work on practice packet, especially titration questions

• Have pages 13-17 completed for Thursday