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F=BIL. Or is it…. F=qvB. Also Determine the direction of the Force! . V. B. Positive Charge is moving. Use: F=qvB Force is going:. V. B. Negative Charge is moving. Use: F=qvB Force is going: Coming out of the page!. B. I. Use: F=BiL Force is going:. F = 1.5x10 -12 N.

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F bil
F=BIL

Or is it…..

F=qvB

Also Determine the direction of the Force! 


V

B

Positive Charge is moving


Use: F=qvB

Force is going:


V

B

Negative Charge is moving


Use: F=qvB

Force is going: Coming out of the page!


B

I


Use: F=BiL

Force is going:


F = 1.5x10-12 N

V = 2.0x107 m/s

Electron

B = ?


Use: F=qvB

1.5 x 10-12= (1.6 x 10-19C) x (2.0x107 m/s) x B

B= .46875 T

Force is going:


B = .15 T

Electron

V = 1.5x106 m/s

F = ?



What is the acceleration of the proton? not feel any force

Mass of a proton is =

1.67262158 × 10-27 kilograms

B = .75 T

Proton

V = 5.8x106m/s


Use: F=qvB not feel any force

F=ma

ma=qvB

(1.67262158 × 10-27 kg)x a = (1.6 x 10-19C) x (5.8x106m/s) x .75 T

a = 4.167 x 1014 m/s/s

Force is going:


1. What is the acceleration of the electron? not feel any force

B = .75 T

2. What is the radius of curvature?

Hint: ac = v2/r

Electron

V = 4.5x107m/s


Use: F=qvB not feel any force

F=mv2/r

mv2/r=qvB

(9.11 × 10-31 kg)(4.5x107m/s)2/r= (1.6 x 10-19C) x (4.5x107m/s) x .75 T

r = 3.4 x 10-4 m

Force is going:


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