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The value of the equilibrium constant, K , is dependent on:

The value of the equilibrium constant, K , is dependent on:. the temperature of the system II. the nature of the reactants and products. At a given temperature, K  = 0.017 for the equilibrium: PCl 5 ( g )      PCl 3 ( g ) + Cl 2 ( g ) What is K for:

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The value of the equilibrium constant, K , is dependent on:

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  1. The value of the equilibrium constant, K, is dependent on:

  2. the temperature of the system • II. the nature of the reactants and products

  3. At a given temperature, K = 0.017 for the equilibrium: • PCl5(g)      PCl3(g) + Cl2(g) • What is K for: • Cl2(g) + PCl3(g)      PCl5(g)?

  4. Answer • 59

  5. Consider the chemical system :CO + Cl2COCl2; K = 4.6 x 109 • How do the equilibrium concentrations of the reactants compare to the equilibrium concentration of the product?

  6. answer • A: They are much smaller

  7. If the concentration of the product were to halved, what would happen to the equilibrium constant?

  8. answer • D: It would not change its value

  9. Find the value of the equilibrium constant (K) (at 500 K) for • N2(g) + 3H2(g) 2NH3(g). • The value for Kp at 500 K is 1.5 x 10–5

  10. answer • 0.025

  11. Consider the following reaction: • 2HF(g)  H2(g) + F2(g) (K = 1.00  x 10–2) • Given 1.00 mole of HF(g), 0.362 mole of H2(g), and 0.750 mole of F2(g) are mixed in a 5.00 L flask, determine in which direction this reaction will shift to reach equilibrium. Support your work with Q.

  12. answer • Q=0.272 • Q>K therefore will shift towards reactants

  13. Consider the reaction H2 + I2    2HI for which K = 44.8 at a high temperature. If an equimolar mixture of reactants gives the concentration of the product to be 0.50 M at equilibrium, determine the equilibrium concentration of the hydrogen.

  14. answer • 7.5 x 10-2 M

  15. Given the equation 2A(g) 2B(g) + C(g). At a particular temperature, K = 1.6 x 104. • If you mixed 5.0 mol B, 0.10 mol C, and 0.0010 mol A in a one-liter container, which direction would the reaction initially proceed?

  16. answer • A: To the left

  17. Given the equation 2A(g) 2B(g) + C(g). At a particular temperature, K = 1.6 x 104. • Addition of chemical B to an equilibrium mixture of the above will

  18. answer • A: Cause [A] to increase

  19. Given the equation 2A(g) 2B(g) + C(g). At a particular temperature, K = 1.6 x 104. • At a higher temperature, K = 1.8 x 10–5. Placing the equilibrium mixture in an ice bath (thus lowering the temperature) will

  20. answer • B: Cause [B] to increase

  21. Given the equation 2A(g) 2B(g) + C(g). At a particular temperature, K = 1.6 x 104. • Raising the pressure by lowering the volume of the container will

  22. answer • A: cause [A] to increase

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