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Example #13: - PowerPoint PPT Presentation

Begin with a drawing. Include all forces with labels, showing any forces that need to be broken into components. (Also go ahead and do any easy calculations, like F g .). Example #13:. F app = ?. F N. Example #13:. F gy. F fric. θ. F gx. F g = 294N.

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PowerPoint Slideshow about ' Example #13:' - tarik-hoffman

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Example #13:

F showing any forces that need to be broken into components. (Also go ahead and do any easy calculations, like app = ?

FN

Fgy

Ffric

θ

Fgx

Fg = 294N

Example #13:

• F the problem will eventually be solved, and set up an equation that will eventually be used to finish the problem.app = Ffric + Fgx

• So this will be great to solve the problem, as soon as we figure out Ffric and Fgx as two little ‘side problems’.

Example #13:

• F the problem will eventually be solved, and set up an equation that will eventually be used to finish the problem.gx is relatively simple, since it’s just a component of Fg.

• Fgx = Fgsinθ = 294sin49o = 221.9N

Example #13:

• F the problem will eventually be solved, and set up an equation that will eventually be used to finish the problem.fric is calculated with the equation

• Ffric = μFN

• But FN is calculated by realizing that the object is in equilibrium in the y-direction.

Example #13:

F the problem will eventually be solved, and set up an equation that will eventually be used to finish the problem.fric = μFN = μFgy = (0.38)(294cos49o)

= 73.29N