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Example Problem: Weak Base

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Calculate the pH of a 0.005M solution of Ammonia

0.005 M -------0 M 0 M

I

C

E

-x ------- +x +x

0.005-x ------- +x +x

Kb=1.8x10-5 =

Assumption check:

https://todaysmeet.com/1CBrindley

0.005 M -------0 M 0 M

I

E

Kb=1.8x10-5=

0.005-x ------- +x +x

Rearranging

=> x=2.91x10-4

Solve for pH

=-log(2.91x10-4)=3.53

10.5