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Statistics Describing Data Using Tables and GraphsPowerPoint Presentation

Statistics Describing Data Using Tables and Graphs

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Statistics Describing Data Using Tables and Graphs

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StatisticsDescribing Data Using Tables and Graphs

Assignment 2

Example Problems

- Objective: Identify the class width, class midpoints, and class boundaries for the given frequency distribution

- Class widthis the difference between two consecutive lower class limits or two consecutive lower class boundaries and thus 53, 52, 51, 50 is a width of 4

- Class midpoints are the values in the middle of the class. Because there is no “exact” middle we find by averaging the class width, that is (53-50)/2 = 1.5
- So each lower value, add 1.5 to get the midpoints of
51.5

55.5

59.5

63.5

67.5

71.5

75.5

- So each lower value, add 1.5 to get the midpoints of

- Class boundariesare the numbers used to separate the classes, but without the gaps created by the class limits
- Find the center of the gaps and don’t forget about the lower boundary
49.5

53.5

57.5

61.5

65.5

69.5

73.5

77.5

- Find the center of the gaps and don’t forget about the lower boundary

- Question: The data represents the daily rainfall (in inches) for one month. Construct a frequency distribution beginning with a lower class limit of 0.00 and use a class width of 0.20. Does the frequency distribution appear to be roughly a normal distribution?

- Answer: What I would do is put the data in numerical ascending order first. Because the frequency is the count and you want to “count” how many data items there are in the range 0.00-0.19. I have them highlighted below (but notice how much easier it would have been if they were sorted)

- Now continue to the 0.20-0.39
- I find 5 values in this range

- Then to 0.40-0.59
- I find two values. I also notice all that is left is 1.34 for I put this “one” in the last row

- For the second part of the problem:
- Does the frequency distribution appear to be roughly a normal distribution?

- Answer: Remember graphically this would be a bell curve. If I visually thought about 22 values in the tail end certainly this is not normal. Normal would have more in the middle and less in the ends.
- In other words No, the distribution is not symmetric and the frequencies do not start off low.

- What if you wanted to actually see the graph of this data in your calculator?
- First you need to enter the data in your calculator
- Press Stat / Edit and press Enter

- First you need to enter the data in your calculator

- You are now looking at a list where you can enter each value
- Enter each value from our example and press enter after each value entered

- You are now looking at a list where you can enter each value
- Enter each value from our example and press enter after each value entered

- Next we will set up the Histogram Window
- Press Window
- We saw from our frequency distribution that our values are between 0 and 1.39. However, we want to have a little room to right and left
- I set my Xmin = -0.5 and Xmax = 1.45

- We saw from our frequency distribution that our values are between 0 and 1.39. However, we want to have a little room to right and left

- Press Window

- The y values are the vertical direction and in our case the frequencies
- These ranged from 0 to 22
- Again make a little more room as I setmine to -0.5 and 22.5 for the Ymin and Ymax

- These ranged from 0 to 22

- Next we will set the Stat Plot
- Press 2nd and then Y= to get to the Stat Plot
- The first plot should be selected so press ENTER

- Press 2nd and then Y= to get to the Stat Plot

- Turn the Stat Plot On by pressing enter
- Down arrow and then to the right to select histogram and press enter
- The Xlist: L1 is where the data is located
- Remember you typed this in the list 1 column

- Press Graph