1 / 16

Chemistry Help Center - Mass Calculation Examples

Learn how to calculate the mass of substances using density and volume measurements. This chapter includes step-by-step examples with clear explanations and helpful tips. Join the Chemistry Help Center today!

swong
Download Presentation

Chemistry Help Center - Mass Calculation Examples

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chapter 1 Examples Matter and Measurement

  2. - To those whom much is given, much is expected. • John F. Kennedy

  3. Chemistry Help Center • M-Th 7:30-9:30 • Keyes 104

  4. Calculate the mass of 10.0 mL of CCl4(l). Given: d = 1.595 g cm-3

  5. Calculate the mass of 10.0 mL of CH4 (l). Given: d = 1.595 g cm-3 w = 1.595 g/mL 10.0 mL w = 15.595 g w = d V

  6. Always check units– helps to correct mistakes • Always give units • % and corresponding ratios are unitless: 15. g of sugar in 100. mL of coffee mass % = (15. g/100. g) 100% = 15. %

  7. Find 12.56 – 11.2

  8. Find 12.56 – 11.2 Align the decimal points: 12.562 SFPDP 11.21 SFPDP 1.36 Final answer: 1.4 1 SFPDP

  9. Find:2.765x10-3  43.2

  10. Find:2.765x10-3  43.2 2.765x10-3 4 SF x 43.23 SF 0.11945 Final answer: 0.119 3 SF

  11. Find:(23.46 – 20.32)/12.34

  12. Find:(23.46 – 20.32)/12.34 Step-by-step: 23.47 – 20.32 = 3.15 2 SFPDP 3.15/12.34 = 0.25445 least precise: 3 SF Final answer: 0.254 3 SF

  13. Keep at least one-extra SF in intermediate calculations Find: (12.65  1.65) – 11.4

  14. Keep at least one-extra SF in intermediate calculations Find: (12.65  1.65) – 11.4 (12.65  1.65) = 20.87 20.87 – 11.4 = 9.47 Final answer: 9.5

More Related