- 78 Views
- Uploaded on
- Presentation posted in: General

GEOMETRY JOURNAL 5

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

GEOMETRY JOURNAL 5

MELANIE DOUGHERTY

- A perpendicular bisector is a line perpendicular to the base of a triangle that bisects it.
- Perpendicular Bisector theorem:
- If a point is on the perpendicular bisector of a segment, then it is equidistant form the endpoints of the segment.

- Converse:
- if a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.

AB = AC

AB = AC

AC = BC

LN = EN

AD = DC

CD = DB

- An angle bisector is a line that divides the angle.
- The angle Bisector theorem:
- If a point is on the bisector of an angle, then it is equidistant from the sides of the angle

- Converse:
- If a point is equidistant from the sides of an angle the it is on the bisector.

BF = FC

<UFK is congruent to <KFC

<EWR is congruent to <RWT

When 3 or more lines intersect at one point

The circumcenter of a triangleisequidistant from the vertices of the triangle.

Circumcenter: where the 3 perpendicular bisectors of a triangle meet

circumcenter

circumcenter

circumcenter

acute

DA = DB = DC

right

DA = DB = DC

DA = DB = DC

obtuse

Incenter of a triangle : where the 3 angle bisectors of a triangle meet

Concurrency of a angle bisectors of a triangle theorem: the incenter of a triangle is equidistant from the sides of the triangle.

incenter

incenter

incenter

ACUTE

RIGHT

DF = DG = DE

DF = DG = DE

DF = DG = DE

OBTUSE

The median of a triangle is a segment whose endpoints are a vertex of the triangle and the midpoint of the opposite side

The centroid of a triangle is the point of concurrency of the medians of a triangle.

Concurrency of medians of a triangle theorem: the centroid of a triangle is located 2/3 of the distance from each vertex to the midpoint of the opposite side.

CMTT

CENTROID

MEDIAN

Altitude: a perpendicular segment from a vertex to the line containing the opposite side

Orthocenter: point where the 3 altitudes of a triangle meet.

Concurrency of altitudes of triangles theorem: the lines containing the altitude are concurrent

A midsegment is a segment that joins the midpoints of two sides of a triangle

Midsegment theorem: a midsegment of a triangle is parallel to a side of the triangle, and its length is half of that side.

midsegment

midsegment

midsegment

AB ll EF, EF = ½ AB

DE ll BC, DE = ½ BC

DE ll AC, DE = ½ AC

If none of the sides of the triangle are congruent then the largest side is opposite the largest angle.

If none of the sides of the triangle are congruent then the shortest side is opposite the smallest angle.

The sum of the lengths of two sides of a triangle is greater than the length of the third side.

Identify what is being proven

Assume that the opposite of your conclusion is true

Use direct reasoning to prove that the assumption has a contradiction

Assume that if the 1st assumption is false then what is being proved is true.

Step 1

Given: triangle JKL is a right triangle

Prove: triangle JKL doesn't have and obtuse angle

Step 2

Assume <K is an obtuse angle

Step 3

m<K + m<L = 90

m<K = 90 – m<L

m<K > 90

90 – m<L > 90

m<L <0 (this is impossible)

Step 4

The original conjecture is true.

If 2 sides of a triangle are congruent to 2 sides of an other triangle and included angles are not congruent, then the longer third side is across from the larger included angle.

Converse: if 2 sides of 2 triangle are congruent to 2 sides of an other triangle and the third sides of an other triangle are not congruent, then the larger included angle is across from the longer third side.