1 / 49

Triangle

Triangle. Ratio of the area of triangles. Theorem 1. Example In the figure, BC// DE, AC= 3 cm and CE= 4 cm. Find. Class work In the figure, PSQ, QXR and RYP are straight lines. If the area of is , find the area of the parallelogram SXRY.

stacy
Download Presentation

Triangle

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Triangle

  2. Ratio of the area of triangles Theorem 1

  3. Example In the figure, BC// DE, AC= 3 cm and CE= 4 cm. Find

  4. Class work In the figure, PSQ, QXR and RYP are straight lines. If the area of is , find the area of the parallelogram SXRY.

  5. Identify the similar triangles first. 81

  6. 81 36 Area of parallelogram = 225 – 81 - 36 = 108 Area of parallelogram is

  7. Triangle

  8. Triangle C height A B base

  9. Triangle

  10. Triangle base height

  11. Triangle

  12. Triangle base height

  13. Area of Triangle C height A B base

  14. What is the relationship between the heights of and ?

  15. Triangles have common height h

  16. For triangles with common height, find

  17. For triangles with commonheight, Theorem 2

  18. Eg.3) Given that BC : DC = 5: 1 Find

  19. Eg.3) Given that BC : DC = 5: 1 Find and have common height,

  20. Eg.3) Given that BC : DC = 5: 1 Find and have common height, = 4

  21. Eg.4) Given that AD = 3 cm and CD = 1 cm. Find

  22. Eg.4) Given that AD = 3 cm and CD = 1 cm. Find and have common height,

  23. Class work 5.) In the figure, find the area of : area of .

  24. Class work 5.) In the figure, find the area of : area of .

  25. Class work 5.) In the figure, find the area of : area of . = 1

  26. 6.) In the figure, given that QX:XR = 5:6 and PY:YR =5:3 calculate the area of (a) (b)

  27. 6.) In the figure, given that QX:XR = 5:6 and PY:YR =5:3 5x 6x

  28. 6.) In the figure, given that QX:XR = 5:6 and PY:YR =5:3 5x 6x

  29. 6.) In the figure, given that QX:XR = 5:6 and PY:YR =5:3 5y 3y 5x 6x

  30. 6.) In the figure, given that QX:XR = 5:6 and PY:YR =5:3 5y 3y 5x 6x

  31. 7) In the figure, PQRS is a rectangle. M is a midpoint of QR. PR and MS intersects at N. Find the area of : area of PQMN.

  32. In the figure, PQRS is a rectangle. M is a midpoint of QR. PR and MS intersects at N. Find the area of : area of PQMN.

  33. In the figure, PQRS is a rectangle. M is a midpoint of QR. PR and MS intersects at N. Find the area of : area of PQMN.

  34. Find the area of : area of PQMN. 4A A = 4

  35. Find the area of : area of PQMN. 4A 2y 2A y A Considering They have the common height.

  36. Find the area of : area of PQMN. 4A 2y 2A y A Hence, = 2A : 5A = 2 : 5

  37. 8.) In the figure, PX:XQ = 1: 2, PY:YR = 3:2. Area of : Area of = ?

  38. In the figure, PX:XQ = 1: 2, PY:YR = 3:2. Area of : Area of = ? and have the common height

  39. In the figure, PX:XQ = 1: 2, PY:YR = 3:2. Area of : Area of = ? and have the common height

  40. In the figure, PX:XQ = 1: 2, PY:YR = 3:2. Area of : Area of = ? and have the common height = 2A : 5A = 2 : 5

  41. 9.) In the figure, PQRS is a rectangle. RSX is a straight line and PX// QS. If the area of PQRS is 24 and Y is a point on QR such that QY :YR = 3:1, find the area of .

  42. 10.) In the figure, if , Find

  43. 10.) In the figure, if , A 3A

  44. 10.) In the figure, if , A x 3A 3x

  45. 10.) In the figure, if , A x 3A 3x 9A

  46. 10.) In the figure, if , A x 3A 3A 3x 9A

  47. 10.) In the figure, if , A x 3A 3A 3x 9A

  48. Ratio of the area of similar triangles Theorem 1

  49. For triangles with commonheight, Theorem 2

More Related