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§ 2.4

§ 2.4. Linear Functions and Slope. x - and y -Intercepts 127. Ax + By = C is called the standard form of the equation of the line. Blitzer, Intermediate Algebra , 5e – Slide # 2 Section 2.4. Graphing Using Intercepts 128. EXAMPLE.

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§ 2.4

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  1. §2.4 Linear Functions and Slope

  2. x- and y-Intercepts 127 Ax + By = C is called the standard form of the equation of the line. Blitzer, Intermediate Algebra, 5e – Slide #2 Section 2.4

  3. Graphing Using Intercepts 128 EXAMPLE Graph the equation using intercepts. SOLUTION 1) Find the x-intercept. Let y = 0 and then solve for x. Replace y with 0 Multiply and simplify Divide by -2 The x-intercept is -6, so the line passes through (-6,0). Blitzer, Intermediate Algebra, 5e – Slide #3 Section 2.4

  4. Graphing Using Intercepts CONTINUED 2) Find the y-intercept. Let x = 0 and then solve for y. Replace x with 0 Multiply and simplify Divide by 4 The y-intercept is 3, so the line passes through (0,3). Blitzer, Intermediate Algebra, 5e – Slide #4 Section 2.4

  5. Graphing Using Intercepts CONTINUED 3) Find a checkpoint, a third ordered-pair solution. For our checkpoint, we will let x = 1 (because x = 1 is not the x-intercept) and find the corresponding value for y. Replace x with 1 Multiply Add 2 to both sides Divide by 4 and simplify The checkpoint is the ordered pair (1,3.5). Blitzer, Intermediate Algebra, 5e – Slide #5 Section 2.4

  6. Graphing Using Intercepts 128 CONTINUED 4) Graph the equation by drawing a line through the three points. The three points in the figure below lie along the same line. Drawing a line through the three points results in the graph of . (0,3) (1,3.5) (-6,0) Blitzer, Intermediate Algebra, 5e – Slide #6 Section 2.4

  7. Slope of a Line 129 The slope m of the line through the two distinct points and is m, where Note that you may call either point However, don’t subtract in one order in the numerator and use another order for subtraction in the denominator - or the sign of your slope will be wrong. Blitzer, Intermediate Algebra, 5e – Slide #7 Section 2.4

  8. Slopes of Lines 130 Check Point 2 a Find the slope of the line passing through the pair of points. Then explain what the slope means. (-3,4) and (-4,-2) SOLUTION The slope is obtained as follows: This means that for every six units that the line (that passes through both points) travels up, it also travels 1 units to the right. Blitzer, Intermediate Algebra, 5e – Slide #8 Section 2.4

  9. Slopes of Lines 130 Check Point 2 b Find the slope of the line passing through the pair of points. Then explain what the slope means. (4,-2) and (-1,5) SOLUTION The slope is obtained as follows: Blitzer, Intermediate Algebra, 5e – Slide #9 Section 2.4

  10. Slopes of Lines 130 Blitzer, Intermediate Algebra, 5e – Slide #10 Section 2.4

  11. Slopes of Lines 131 Blitzer, Intermediate Algebra, 5e – Slide #11 Section 2.4

  12. Slopes of Lines 131 EXAMPLE Give the slope and y-intercept for the line whose equation is: 3x - 5y = 7 SOLUTION Hint: You should solve for y so as to have the equation in slope intercept form. 3x - 5y = 7 3x - 3x - 5y = -3x+7 Subtract 3x from both sides -5y = -3x+7 Simplify Divide both sides by -5 Simplify Therefore, the slope is 3/5 and the y-intercept is -7/5. Blitzer, Intermediate Algebra, 5e – Slide #12 Section 2.4

  13. Slopes of Lines 132 Check Point 3 Give the slope and y-intercept for the line whose equation is: 8x - 4y = 20 SOLUTION Solve for y so as to have the equation in slope intercept form. 8x - 4y = 20 8x - 8x - 4y = -8x+20 Subtract 8x from both sides -4y = -8x+20 Simplify Divide both sides by -4 Simplify Therefore, the slope is 2 and the y-intercept is -5. Blitzer, Intermediate Algebra, 5e – Slide #13 Section 2.4

  14. Slopes of Lines 132 Blitzer, Intermediate Algebra, 5e – Slide #14 Section 2.4

  15. Graphing Lines 132 EXAMPLE Graph the line whose equation is f(x) = 2x + 3. SOLUTION The equation f(x) = 2x + 3 is in the form y = mx + b. The slope is 2 and the y-intercept is 3. Now that we have identified the slope and the y-intercept, we use the three steps in the box to graph the equation. Blitzer, Intermediate Algebra, 5e – Slide #15 Section 2.4

  16. Graphing Lines CONTINUED 1) Plot the point containing the y-intercept on the y-axis. The y-intercept is 3. We plot the point (0,3), shown below. (0,3) Blitzer, Intermediate Algebra, 5e – Slide #16 Section 2.4

  17. Graphing Lines CONTINUED 2) Obtain a second point using the slope, m. Write m as a fraction, and use rise over run, starting at the point containing the y-intercept, to plot this point. We express the slope, 2, as a fraction. (1,5) (0,3) We plot the second point on the line by starting at (0,3), the first point. Based on the slope, we move 2 units up (the rise) and 1 unit to the right (the run). This puts us at a second point on the line, (1,-1), shown on the graph. Blitzer, Intermediate Algebra, 5e – Slide #17 Section 2.4

  18. Graphing Lines CONTINUED 3) Use a straightedge to draw a line through the two points. The graph of y = 2x + 3 is show below. (1,5) (0,3) Blitzer, Intermediate Algebra, 5e – Slide #18 Section 2.4

  19. Graphing Lines 133 Check Point 4 Graph the line whose equation is f(x) = 4x - 3. SOLUTION The equation f(x) = 4x - 3 is in the form y = mx + b. The slope is 4 and the y-intercept is -3. With the slope and the y-intercept, graph the equation. Blitzer, Intermediate Algebra, 5e – Slide #19 Section 2.4

  20. Horizontal and Vertical Lines 134 EXAMPLE 6 on page 134 Graph the linear equation: y = -4. SOLUTION All ordered pairs that are solutions of y = -4 have a value of y that is always -4. Any value can be used for x. Let’s select three of the possible values for x: -3, 1, 6: (1,-4) (-3,-4) (6,-4) Upon plotting the three resultant points and connecting the points with a line, the graph to the right is the solution. Blitzer, Intermediate Algebra, 5e – Slide #20 Section 2.4

  21. Horizontal and Vertical Lines 135 EXAMPLE – similar to Ex 7 on page 135 Graph the linear equation: x = 5. SOLUTION All ordered pairs that are solutions of x = 5 have a value of x that is always 5. Any value can be used for y. Let’s select three of the possible values for y: -3, 1, 5: (5,5) (5,1) (5,-3) Upon plotting the three resultant points and connecting the points with a line, the graph to the right is the solution. Blitzer, Intermediate Algebra, 5e – Slide #22 Section 2.4

  22. Slope as Rate of Change p 136 • A linear function that models data is described. Slope may be interpreted as the rate of change of the dependent variable per unit change in the independent variable. • Find the slope of each model. • Then describe what this means in terms of the rate of change of the dependent variable y per unit change in the independent variable x. Blitzer, Intermediate Algebra, 5e – Slide #23 Section 2.4

  23. Slope as Rate of Change p 136 EXAMPLE 8 Using the Figure 2.27 graph on page 136 which show the percentage of Americans in two age groups who reported using illegal drugs in the previous month. SOLUTION • Find the slope of the line for the 12-17 age group. • The slope indicates that for the 12-17 age group, the percentage reporting using illegal drugs in the previous month decreased by approximately 0.57% per year. The rate of change is a decrease of approximately 0.57%. Blitzer, Intermediate Algebra, 5e – Slide #23 Section 2.4

  24. Slope as Rate of Change p 136 Check Point 8 Using the Figure 2.27 graph on page 136 to find the slope of the line segment for the 50-59 age group. Express the slope correct to two decimal places and describes what it represents. SOLUTION • Find the slope of the line for the 50-59 age group. • For the 50-67 age group, the percentage reporting using illegal drugs in the previous month increased by approximately 0.57% per year. Blitzer, Intermediate Algebra, 5e – Slide #23 Section 2.4

  25. Modeling with Slope-Intercept p 139 EXAMPLE 10 Using the Figure 2.31(b) scatter plot on page 138 find a function in the form T(x)=mx+b.that models the average ticket price for a movie T(x), x years after 1990 and use the model to predict the average ticket price in 2010. SOLUTION • Find the slope. • The average ticket price for a movie, T(x), x years after 1990 can be modeled by the linear function. The slope indicates that ticket prices increase $0.15 per year. Blitzer, Intermediate Algebra, 5e – Slide #23 Section 2.4

  26. Modeling with Slope-Intercept p 139 EXAMPLE 10, continued • Because 2010 is 20 years after 1990, substitute 20 for x and evaluate. • The model predicts an average ticket price of $7.23 in 2010. • Try doing Check Point 10 on your own. • Note that vertical intercept and y-intercept are the same. Blitzer, Intermediate Algebra, 5e – Slide #23 Section 2.4

  27. DONE

  28. Graphing Using Intercepts 129 Check Point 1 Graph the equation using intercepts. 1) Find the x-intercept. Let y = 0 and then solve for x. The x-intercept is 2, so the line passes through (2,0). 2) Find the y-intercept. Let x = 0 and then solve for y. The y-intercept is -3, so the line passes through (0,-3). 3) Find a checkpoint, a third ordered-pair solution. Let x=4. The checkpoint is the ordered pair (4,3). Blitzer, Intermediate Algebra, 5e – Slide #28 Section 2.4

  29. Slopes of Lines EXAMPLE Find the slope of the line passing through the pair of points. Then explain what the slope means. (-7,-8) and (4,-2) SOLUTION Remember, the slope is obtained as follows: This means that for every six units that the line (that passes through both points) travels up, it also travels 11 units to the right. Blitzer, Intermediate Algebra, 5e – Slide #29 Section 2.4

  30. Slope as Rate of Change p 136 EXAMPLE The linear function y = 2x + 24 models the average cost in dollars of a retail drug prescription in the United States, y, x years after 1991. SOLUTION • The slope of the linear model is 2. • This means that every year (since 1991) the average cost in dollars of a retail drug prescription in the U.S. has increased approximately $2. Blitzer, Intermediate Algebra, 5e – Slide #23 Section 2.4

  31. Slope as Rate of Change 130 The change in the y values is the vertical change or the “Rise”. The change in the x values is the horizontal change or the “Run.” m is commonly used to denote the slope of a line. The absolute value of a line is related to its steepness. When the slope is positive, the line rises from left to right. When the slope is negative, the line falls from left to right. Blitzer, Intermediate Algebra, 5e – Slide #31 Section 2.4

  32. Slope Intercept Form 131 In the form of the equation of the line where the equation is written as y = mx + b, it is true that if x = 0, then y = b. Therefore, b is the y intercept for the equation of the line. Furthermore, the x coefficient mis the slope of the line. Blitzer, Intermediate Algebra, 5e – Slide #32 Section 2.4

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