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# Probability and Multiple Trait Inheritance - PowerPoint PPT Presentation

Probability and Multiple Trait Inheritance. Punnett Squares and Probability. All ratios established from a Punnett square, represent probabilities. Probability can be thought of as a score out of 1 that indicates the likelihood of an event. 0.50 event will occur half of the time

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### Probability and Multiple Trait Inheritance

Punnett Squares and Probability

• All ratios established from a Punnett square, represent probabilities.

• Probability can be thought of as a score out of 1 that indicates the likelihood of an event.

• 0.50 event will occur half of the time

• 1.00 event will occur all of the time

• Product Law: The probability of two or more outcomes occurring is equal to the product of their individual probabilities.

Monohybrid Crosses

• Thalassemia is an autosomal recessive condition that affects hemoglobin production and can cause anemia in affected persons

H = normal hemoglobin h = thalassemia

• Consider two parents, both heterozygous for thalassemia:

Hh X Hh, what is the probability that they will have an affected child?

• What is the probability of a couple having 3 female children?

• If a couple has 2 children, what is the probability they will have a boy and a girl?

• If their first child is a girl, what is the probability that the next two will be girls?

• The pedigree traces the occurrence of deafness throughout a family.

• If individual IV-2 marries a deaf woman, what is the probability that any of their children will be deaf?

Dihybrid determining the mode of inheritance is key to making an accurate prediction. Crosses

• In cocker spaniels:

• black coat colour (B) is dominant to red (b)

• solid colour (S) is dominant to white spotting (s).

• If two dogs, heterozygous for both traits are mated, what is the probability they will have red offspring with white spotting?

Warm up determining the mode of inheritance is key to making an accurate prediction.

• In mice, black coat (B) is dominant to white coat (b) and black eyes (E) are dominant to pink eyes (e).

• A male, heterozygous for both traits, is mated to a pure-breeding recessive female.

• Show the genotypes for each parent

• Show the possible sex cells each parent could produce

• Construct a Punnett square to determine all possible genotypes and phenotypes in the F1 generation.