Advanced math topics
This presentation is the property of its rightful owner.
Sponsored Links
1 / 7

Advanced Math Topics PowerPoint PPT Presentation


  • 67 Views
  • Uploaded on
  • Presentation posted in: General

Advanced Math Topics. 5.3 Conditional Probability. Notes. With Conditional Probability , the probability of an event changes on what has happened in previous events. p(A | B). = probability of A given that B has happened. p(A and B). p(A | B) =. p(B).

Download Presentation

Advanced Math Topics

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript


Advanced math topics

Advanced Math Topics

5.3 Conditional Probability


Advanced math topics

Notes

With Conditional Probability, the probability of an event changes on what

has happened in previous events.

p(A | B)

= probability of A given that B has happened

p(A and B)

p(A | B)=

p(B)

We can analyze why this is the formula…


Advanced math topics

There are 2 green, 2 blue, and 2 red marbles in a bag. You selected 2 marbles

Find p(picking a blue and a green).

p(blue) x

p(green | blue)

p(blue & green) =

Rearrange this formula to isolate

p(green I blue):

2/6 x

2/5

p(blue & green) =

= 4/30

= 2/15

p(blue) x

p(green | blue)

p(blue & green) =

p(blue)

p(blue)

p(blue & green)

= p(green | blue)

p(blue)

p(blue & green)

p(green | blue) =

p(blue)

The conclusion…

p(A & B)

p(A | B) =

p(B)


Advanced math topics

From the HW P. 256

2) 72% of all hospitalized senior citizen patients have medical insurance. The

records indicate that 32% of all patients are females and have medical

insurance. If a patient is selected at random, what is the probability that the patient

is a female given that the patient has medical insurance?

p(A & B)

p(A | B) =

p(B)

p(female & insur.)

p(female | insurance) =

p(insur.)

.32

p(female | insurance) =

.72

44.44%

p(female | insurance) =


Advanced math topics

From the HW P. 256

4) It was found that that 22% of females between the age of 20-30 years jog to

stay in shape. 12% of the females jog and exercise at a health spa. If a female

between the age of 20 to 30 years who is jogging is randomly selected, what is

the probability that she exercises at a health spa?

p(A & B)

p(A | B) =

p(B)

p(spa & jog)

p(spa | jog) =

p(jog)

.12

p(spa | jog) =

.22

54.55%

p(spa | jog) =


Advanced math topics

From the HW P. 256

11) On the board together.


Advanced math topics

HW

P. 256 #2-11


  • Login