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Proofs

Proofs. Proof of A1: Let a=(yz) -1 and b=(xy)z=[x(yz)]s=(sx)(yz)=(sx)a -1 , where s=(x,y,z). Then x = s -1 (ba). (xz)y = {[s -1 (ba)]z}y = [(ba)z](ys -1 ) = [{[(xy)z]a}z](ys -1 ) = {(xy)[(za)z]}y s -1 = x ? {y[(za)z]}y ? s -1

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Proofs