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Violating arc - PowerPoint PPT Presentation

15.082 and 6.855J

15.082 and 6.855J. Label Correcting Algorithm. An Example. ?. ?. 2. 4. 2. 3. 3. 3. 1. ?. ?. -2. 6. 1. 5. 7. 0. Initialize. 2. 3. 4. 3. d(1) := 0; d(j) := ? for j ? 1. -4. 3. 6. ?. ?. In next slides: the number inside the node will be d(j).

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212 views • 11 slides

OPIM 915 -- #7 Animation

OPIM 915 -- #7 Animation. Label Correcting Algorithm. An Example. ?. ?. 2. 4. 2. 3. 3. 3. 1. ?. ?. -2. 6. 1. 5. 7. 0. Initialize. 2. 3. 4. 3. d(1) := 0; d(j) := ? for j ? 1. -4. 3. 6. ?. ?. In next slides: the number inside the node will be d(j).

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217 views • 11 slides

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15.082 and 6.855J

OPIM 915 -- #7 Animation