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Section 15.8.

Section 15.8. Lagrange Multipliers. FREE EXTREMUM VERSUS CONSTRAINED EXTREMUM PROBLEMS. To find the minimum value of f ( x , y , z ) = x 2 + 2 y 2 + z 4 + 4 is a free extremum problem. To find the minimum of f ( x , y , z ) = x 2 + 2 y 2 + z 4 + 4

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Recall :

Recall :. The area of the parallelogram determined by two 3-vectors is the length of cross product of the two vectors.

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Sphere x2 - PowerPoint PPT Presentation

Section 15.8.

Recall :