'Monatomic gas' presentation slideshows

A question with too many solutions: Proton size puzzle

A question with too many solutions: Proton size puzzle. Chung-Wen Kao Chung-Yuan Christian University, Taiwan. 2012. 12.14 Institute of Physics, Academic Sinica. Discovery of Proton(1917).

989 views • 82 slides

731 views • 67 slides

Review of CHM 1316

624 views • 44 slides

Heat Transfer Materials Storage, Transport, and Transformation Part I: Physics

A Short Course by Reza Toossi, Ph.D., P.E. California State University, Long Beach. Heat Transfer Materials Storage, Transport, and Transformation Part I: Physics. Outline. Atomic and Molecular Bonds Energy Carriers Specific Heat Thermal Conductivity Discussions. History.

521 views • 42 slides

University of California, Berkeley March 9, 2007

University of California, Berkeley March 9, 2007. Use of NEXAFS in Materials Science. Tony van Buuren Nanoscale Synthesis and Characterization Laboratory Lawrence Livermore National Laboratory and UC Merced School of Natural Sciences. Outline. Overview of the X-ray absorption process

516 views • 34 slides

Adiabatic Reversible Process: q=0 Ideal gas

Grains of sand. Adiabatic walls. Adiabatic Reversible Process: q=0 Ideal gas. Small adiabatic change (dV,dT)). TexPoint fonts used in EMF. Read the TexPoint manual before you delete this box.: A A A A A A A A A. isotherm : pV = constant.

1.18k views • 29 slides

Specific heat of gases

Specific heat of gases. Specific heat of monatomic gas I. Add heat keeping the volume constant. Energy can only go into kinetic energy of atoms: Conclusion: . Specific heat of a monatomic gas II.

1.4k views • 26 slides

825 views • 23 slides

Lecture 30

Lecture 30. Goals:. Wrap up chapter 20. Review for the final. Final exam on Friday, Dec 23, at 10:05 am in BASCOM 272. Final will cover Chapters 1-20 (excluding Chapter 13). Semi-cumulative. HW 12 due tomorrow night. The Doppler effect.

385 views • 21 slides

Lecture 26

Lecture 26. Goals:. Chapters 18, entropy and second law of thermodynamics Chapter 19, heat engines and refrigerators. No lab this week. Equipartition theorem. Things are more complicated when energy can be stored in other degrees of freedom of the system. monatomic gas: translation

213 views • 21 slides

Lecture 30

Lecture 30. Goals:. Review for the final. Final exam on Monday, Dec 20, at 5:05 pm, at Sterling 1310, Graham 19. HW 11 due tonight. Waves. The figure shows a snapshot graph D ( x , t = 2 s) taken at

360 views • 20 slides

The Standard Model of the Atom

The Standard Model of the Atom. Reminders. In-class Quiz #6 today ( start or end of class?) Mallard-based reading quiz due prior to start of class on Thursday, April 24 LAB D1-LFA: Light From Atoms due by 4:00 PM Friday (last lab). Optional CCR extra credit project due May 1

350 views • 19 slides

Heat

643 views • 17 slides

Thermal & Kinetic Philip Moriarty School of Physics & Astronomy

298 views • 17 slides

CHE-20004: PHYSICAL CHEMISTRY STATISTICAL THERMODYNAMICS: LECTURE 3 Dr Rob Jackson

CHE-20004: PHYSICAL CHEMISTRY STATISTICAL THERMODYNAMICS: LECTURE 3 Dr Rob Jackson Office: LJ 1.16 r.a.jackson@keele.ac.uk http://www.facebook.com/robjteaching. Statistical Thermodynamics: topics for lecture 3. Summary from lecture 2 Calculation of the Gibbs free energy Monatomic gas

380 views • 16 slides

266 views • 16 slides

Lecture 25

Lecture 25. Goals:. Chapters 18, micro-macro connection. Third test on Thursday at 7:15 pm. Nitrogen molecules near room temperature. Percentage of molecules. 15. 10. 5. (m/s). 0-100. 1100-1200. 1000-1100. 800-900. 900-1000. 300-400. 600-700. 200-300. 400-500. 500-600.

167 views • 16 slides

The Micro/Macro Connection Readings: Chapter 18

164 views • 16 slides

Lecture 12

Lecture 12. Stellar structure equations. Convection. A bubble of gas that is lower density than its surroundings will rise buoyantly

225 views • 13 slides

14.5 Distribution of molecular speeds

14.5 Distribution of molecular speeds. For a continuum of energy levels, where and. Combining the above equations, one has ? is a kinetics energy calculated through (1/2)mv 2, thus d ? = mv d v The above equation can be transformed into (in class demonstration).

254 views • 10 slides