'Mol naoh' presentation slideshows

Chapter 11 Thermochemistry - Heat and Chemical Change

Chapter 11 Thermochemistry - Heat and Chemical Change. 11.3 Heat and changes of state. Things you will learn. Classify the changes that occur during melting/freezing and boiling/condensing Calculate heat changes during changes of state

320 views • 19 slides

Titrations

Titrations. Main Idea: Titrations are an application of acid-base neutralization reactions that require the use of an indicator. Stoichiometry.

362 views • 18 slides

Titrations

Titrations. Main Idea: Titrations are an application of acid-base neutralization reactions that require the use of an indicator. Stoichiometry.

596 views • 18 slides

25) 40.0 g/mol NaOH, 110.98 g/mol CaCl 2 98.14 g/mol KC 2 H 3 O 2 211.64 g/mol Sr(NO 3 ) 2

25) 40.0 g/mol NaOH, 110.98 g/mol CaCl 2 98.14 g/mol KC 2 H 3 O 2 211.64 g/mol Sr(NO 3 ) 2 149.10 g/mol (NH 4 ) 3 PO 4 26) 46.07 g/mol C 2 H 5 OH 342.30 g/mol C 12 H 22 O 11 27.03 g/mol HCN 153.81 g/mol CCl 4 , 18.02 g/mol H 2 O. 27) 319 g H 2 SO 4 28) 5.93 g ZnCl 2

450 views • 10 slides

Stoichiometry - House Method

Stoichiometry - House Method. 1. Start with a balanced chemical equation. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3. Stochiometry - House Method.

245 views • 10 slides

Making Molar Solutions

263 views • 9 slides

Stoichiometry - House Method

Stoichiometry - House Method. 1. Start with a balanced chemical equation. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3. Stoichiometry - House Method. 2. Place the given information above the proper compounds in the equation. 120 g. X g.

227 views • 9 slides

Making Molar Solutions

259 views • 9 slides