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Civil engineer deposits - PowerPoint PPT Presentation

Chapter 2, Solution 3. F = 200,000(F/P,10%,3) = 200,000(1.3310) = $266,200

Chapter 2, Problem 1. Find the correct numerical value for the following factors from the interest tables. 1. ( F / P ,8%,25) 2. ( P / A ,3%,8) 3. ( P / G ,9%,20) 4. ( F / A ,15%,18) 5. ( A / P ,30%,15).

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Civil engineer deposits - PowerPoint PPT Presentation

Chapter 2, Solution 3. F = 200,000(F/P,10%,3) = 200,000(1.3310) = $266,200