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CH12.Problems

CH12.Problems. JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) ? M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3) (3 L/4) M1 = 3(M2+M3) = 3* 4 = 12kg Only Torques, no forces!. -Ta + Tc cos30 = 0 Tc Sin30 -240 = 0 Only forces no torques. Project!

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Ch12 problems - PowerPoint PPT Presentation

CH12.Problems