'4 2x' presentation slideshows

More on Solving Equations

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Equations

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More on Solving Equations

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Reasoning with Properties of Algebra & Proving Statements About Segments

Reasoning with Properties of Algebra & Proving Statements About Segments. CCSS: G-CO.12. CCSS:G-CO.12.

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More on Solving Equations

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Solving Exponential and Logarithmic Equations

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Pre-Algebra Test Prep Chapter 8 Equations/Inequalities

Pre-Algebra Test Prep Chapter 8 Equations/Inequalities. Planner Notes: Study Practice Test Test on Monday!!! Bellwork: Solve 2(9s + 3) = 6(3s + 1) Warm-Up Song. Bellwork: 2(9s + 3) = 6(3s + 1). 18s + 6 = 18s + 6 Distribute -6 = -6 Subtract 6

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Polynomial Project

Polynomial Project. Introduction.

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Objective- To use the distributive property to simplify variable expressions.

Objective- To use the distributive property to simplify variable expressions. Distributive Property. a(b + c) = ab + ac. Order of Operations. Distributive Property. 6(3 + 5). 6(3 + 5). 6(3) + 6(5). 6(8). 48. 18 + 30. 48. Why distribute when order of operations is faster ?.

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Warm-Up

Warm-Up. 1) Sketch a graph of two lines that will never intersect. 2) Sketch a graph of two lines that intersect at one point. 3) Sketch a graph of two lines that intersect at every point (an infinite number of points). B10 Solving Systems of Equations by Graphing. Objectives:

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Section 2.4: Reasoning in Algebra

Section 2.4: Reasoning in Algebra. Objective: To connect reasoning in algebra and geometry. Reasoning in algebra. In Geometry, we accept postulates and properties as true. We use properties of equality to solve problems.

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Bell Ringer:

Homework: Textbook- Read 518-520 Do: P. 520 -558: 2,3,4,5,8,14,22,28 , 34. Objective: SWBAT: factor trinomials of the form ax 2 + bx + c. Bell Ringer:.

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Algebra 1

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The Distributive Property

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Real Life E xamples on: Adding and Multiplying Polynomials

Real Life E xamples on: Adding and Multiplying Polynomials. By: Sarah Santamaria Teacher: Mr. Miguel Class: Algebra 2 MT 2 Level 4. What are Polynomials?. Polynomial: Expression of more than two algebraic terms that contain different powers of the same variable(s).

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X=y^2+1 x=3 solution:- R=3-x =3-(y^2+1) V=? ? (3-(y^2+1))

X=y^2+1 x=3 solution:- R=3-x =3-(y^2+1) V=? ? (3-(y^2+1)). Y=x^2-2x Y=4 y=x X^2-2x=x X^2-3x=0 X(x-3)=0 X=0 x=3 R(x)=4-x^2-2x r (x)=4-2x R^2(x)=16-8(x^2-2x)+(x^2-2x)^2 16-8x^2+16x+x^4-4x^3+4x^2 =16-4x^2+16x+x^4-4x^3 r^2(x)=(4-x)^2 =16-8x+x^2.

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