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4 15 60 miles - PowerPoint PPT Presentation

5.1 Accumulated Changes

5.1 Accumulated Changes. Example 1 : An objects travels with a velocity of 15 mph. What is the distance traveled after 4 hours. The velocity is constant and the distance is: S = v.t = (4 ) (15) = 60 miles. v. Distance = area = (4)(15) =60. 15. t. 1. 2. 3. 4.

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3.1 Accumulated Changes

3.1 Accumulated Changes. Example 1 : An objects travels with a velocity of 15 mph. What is the distance traveled after 4 hours. The velocity is constant and the distance is: S = v.t = (4 ) (15) = 60 miles. v. Distance = area = (4)(15) =60. 15. t. 1. 2. 3. 4.

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136 views • 7 slides

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4 15 60 miles - PowerPoint PPT Presentation

5.1 Accumulated Changes

3.1 Accumulated Changes